<span>A)Both m(x) and p(x) cross the x-axis at 7.
B)Both m(x) and p(x) cross the y-axis at 7.
C)Both m(x) and p(x) have the same output value at x = 7.
D)Both m(x) and p(x) have a maximum or minimum value at x = 7.
m(x) = p(x) at x = 7
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True statement about x = 7.
C)Both m(x) and p(x) have the same output value at x = 7. </span><span>
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Answer:
First, assign a value to x.<em> x</em> will be 2 in this case.
Next, multiply x by itself, because that is what exponent 2, or squared, means. 2 x 2 = 4
Now, multiply 4 by 7. 4 x 7 = 28
Next, find the value of <em>9x</em>.
The value of 9x will be 9 times a number, x, also known as 2 in this scenario. 9 x 2 = 18
Then, subtract 28 from 18. 28 - 18 = 10
Lastly, subtract 10. 10 - 10 = 0
Therefore,
The answer is 0. <em>Product may vary depending on value assigned to x.</em>
Answer:
Step-by-step explanation:
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Answer:
Step-by-step explanation:
The answer is 5th 6th
Answer:
a = √[(c — b)(c + b)]
Step-by-step explanation:
a^2 + b^2 = c^2
We can make "a" the subject by doing the following:
a^2+ b^2 = c^2
Subtract b^2 from both side:
a^2 = c^2 — b^2
Take the square root of both side
a = √(c^2 — b^2)
Since we have difference of two squares, we can simplify further as:
a = √[(c — b)(c + b)]