Question

What is the solution of the linear-quadratic system of equations? y=x^2+5x−3 y−x=2

Answer 1

y = x²+5x−3

y−x = 2     =    y = x+2

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x+2 = x²+5x-3

x² + 4x -5 =0

(x+5)(x-1)=0

x ₁= -5

x₂ = 1

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y₁ = -5+2

y₁ = -3

y₂ = 1+2

y₂ = 3

Answer 2

Answer:

x =  1, y = 3

x = -5, y = -3

Step-by-step explanation:

Point Form:

(1,3) , (-5, -3)