What is the solution of the linear-quadratic system of equations?
y=x^2+5x−3
y−x=2
2 answers:
y = x²+5x−3
y−x = 2 = y = x+2
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x+2 = x²+5x-3
x² + 4x -5 =0
(x+5)(x-1)=0
x ₁= -5
x₂ = 1
-----------------------------------
y₁ = -5+2
y₁ = -3
y₂ = 1+2
y₂ = 3
Answer:
x = 1, y = 3
x = -5, y = -3
Step-by-step explanation:
Point Form:
(1,3) , (-5, -3)
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