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3 years ago

What is 7,5444+789=?

Mathematics

2 answers:

liraira [26]3 years ago

4 0

The answer would 76233

lisov135 [29]3 years ago

3 0

Answer:

76233

Step-by-step explanation:

Add the numbers together:

75444 + 789 = 76233

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What lump sum do parents need to deposit in an account earning 9%, compounded monthly, so that it will grow to $100,000 for thei

gogolik [260]

Answer:

They need to deposit $31,172.49

Step-by-step explanation:

The compound interest formula is given by:

$A = P(1 + \frac{r}{n})^{nt}$

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time the money is invested or borrowed for, in years.

In this problem

We want to find P for which $A = 100000$ when $r = 0.09, n = 12, t = 13$

$A = P(1 + \frac{r}{n})^{nt}$

$100000 = P(1 + \frac{0.09}{12})^{12*13}$

$3.208P = 100000$

$P = \frac{100000}{3.208}$

$P = 31172.49$

They need to deposit $31,172.49

6 0

3 years ago

A bicycle tire has a radius of 26 inches. How many revolutions will this tire make if the bicycle is pedaled 1 mile? (Use 3.14 f

Fittoniya [83]

How far does a wheel move when it rotates once? The length of the outside of the tyre? Isn't that the same as the circumference?

4 0

2 years ago

Suppose that a company prints baseball cards. They claim that 30% of the cards feature rookies, 60% feature veterans, and 10% fe

liraira [26]

Answer:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

Step-by-step explanation:

On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

And in order to test it we need to have observed and expected values. On this case we can calculate the Expected values like this

$E_{rookies}=50*0.3=15$

$E_{veterans}=50*0.6=30$

$E_{All stars}=50*0.1=5$

The observed values are not provided. The statistic on this case is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i) -E_i}{E_i}$

And this statistic follows a chi square distribution with k-1 degrees of freedom on this case k=3, since we have 3 groups.

We can calculate the p valu like this:

$P(\chi^2 > \chi^2_{calculated})=p_v$

And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.

5 0

3 years ago

6) Kate wants to buy some daisies for $6.99, some potting soil for $3.98, and a ceramic pot for $7.95. She has $20.00. Which num

Mama L [17]

By taking a subtraction, we will see that the change that Kate receives is $1.08

<h3></h3><h3>How to get the change?</h3>

The change will be given by the difference between what Kate has, and the cost of all the items she buys.

She has $20.00, and the costs are: $6.99, $3.98, and $7.95.

Then the change will be:

C = $20.00 - $6.99 - $3.98 - $7.95 = $1.08

We conclude that the change is $1.08

If you want to learn more about subtractions, you can read:

brainly.com/question/2475734

5 0

2 years ago

How to solve this plss frac{(\sqrt{(3)})^{5}}{((\sqrt{(3)})^{-4})}=(\sqrt{(3)})^{(2k+1)

dusya [7]

Answer:

k = 4

Step-by-step explanation:

Given equation:

$\dfrac{(\sqrt{3})^{5}}{(\sqrt{3})^{-4}}=(\sqrt{3})^{(2k+1)}$

$\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies (\sqrt{3})^{(5-(-4))}=(\sqrt{3})^{(2k+1)}$

$\implies (\sqrt{3})^{9}=(\sqrt{3})^{(2k+1)}$

$\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):$

$\implies (\sqrt{3})^{9}=(\sqrt{3})^{(2k+1)}$

$\implies 9=2k+1$

$\implies 2k=8$

$\implies k=4$

6 0

2 years ago