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Lyrx [107]
3 years ago
15

If you have 14 feet of fencing, what are the areas of the different rectangles you could enclose with the fencing? Consider only

whole number dimensions
Mathematics
1 answer:
disa [49]3 years ago
8 0

Answer:

Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²

Step-by-step explanation:

Feets of fencing = 14

Perimeter = 14

Let x = Length y = width

Perimeter = 2(x + y)

For x = 1

2(1 + y) = 14

1 + y = 7

y =6

Area of rectangle ; x *y = 1 * 6 = 6 ft²

For x = 2

2(2 + y) = 14

2 + y = 7

y = 5

Area of rectangle ; x *y = 2 * 5 = 10 ft²

For x = 3

2(3 + y) = 14

3 + y = 7

y =4

Area of rectangle ; x *y = 3 * 4 = 12 ft²

For x = 4

2(1 + y) = 14

4 + y = 7

y = 3

Area of rectangle ; x *y = 4 * 3 =12 ft²

Hence, Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²

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Lines L and M are parallel. Lines t^1 and t^2 are transversals. What is m&lt;1 if m&lt;4=65*? Justify your answer. (Ps- there is
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The complete question in the attached figure

we know that
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