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bekas [8.4K]
3 years ago
8

Can some one help me plz trying to figure out? Need help ASAP

Mathematics
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

a. = -35 \\ b. = 9a + 1 \\ c. = -35

Step-by-step explanation:

a. \\  =  >  \: 7a - 1 + 2a + 2 \\  \\  =  > 7( - 4) - 1 + 2( - 4) + 2 \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \: (a =  - 4) \\  \\  =  >  - 28 - 1 - 8 + 2 \\  \\  =  >  - 37 + 2 \\  \\  =  >  - 35 \\  \\  \\ b. \\  =  > 7a - 1 + 2a + 2 \\  \\  =  > 7a + 2a - 1 + 2 \\  \\  =  > 9a + 1 \\  \\  \\ c. \\  =  > 9a + 1 \\  \\  =  > 9( - 4) + 1 \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \: (a  =  - 4) \\  \\  =  >  - 36 + 1 \\  \\  =  >  - 35

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Christina had a total of $120 to spend while shopping. She already spent $68 on clothes . She wants to buy some video games that
avanturin [10]

Answer:

5 video games.

Step-by-step explanation:

In order to find the total number of video games that Tracy can buy with the money, she has we first need to find how much money she has left after buying the clothes. To do this we subtract the amount she spent on clothes by the initial total that Christina had.

120 - 68 = 52

Now that we know Christina has a remaining $52, we can divide this amount by the value of each individual game ($10) in order to calculate how many she can actually afford.

52 / 10 = 5.2

Finally, we can see that she can afford to only buy 5 video games.

4 0
2 years ago
If g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down, what would the
Kitty [74]

Answer:

The new equation is h(x)=4(x-7)^2-19

Step-by-step explanation:

Given : Function g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down.

To find : What would the  new equation be?​

Solution :

Shifting to the right with 'a' unit is

f(x)→f(x-a)

So, shifting g(x) 7 units to the right is

h(x) = 4(x-7)^2-16

Shifting to the down with 'b' unit is

f(x)→f(x)-b

So, shifting g(x) 3 units down is

h(x)=(4(x-7)^2-16)-3

h(x)=4(x-7)^2-19

The new equation is h(x)=4(x-7)^2-19

8 0
2 years ago
Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre
choli [55]

Answer:

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

\hat p=\frac{46}{115}=0.4 estimated proportion of people that have traded in their old car

p_o=0.48 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:  

Null hypothesis:p\geq 0.48  

Alternative hypothesis:p < 0.48  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

4 0
3 years ago
Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear
Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 1.35.
  • The standard deviation is of \sigma = 0.33.

Item 1:

Considering his ratio, we have that X = 0.73, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 1.35}{0.33}

Z = -1.88

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.96 - 1.35}{0.33}

Z = 1.85

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

7 0
2 years ago
I don't know what the answer is to divide 180 in a ratio of 4:5:9
Karolina [17]
Hello there,

First you need to add together the numbers.
4+5+9 = 18
Divide the total by this,
180 / 18 = 10
Multiply each number by 10.
40:50:90.

Hope This Helps You!
Good Luck Studying :)
4 0
3 years ago
Read 2 more answers
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