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bekas [8.4K]
3 years ago
8

Can some one help me plz trying to figure out? Need help ASAP

Mathematics
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

a. = -35 \\ b. = 9a + 1 \\ c. = -35

Step-by-step explanation:

a. \\  =  >  \: 7a - 1 + 2a + 2 \\  \\  =  > 7( - 4) - 1 + 2( - 4) + 2 \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \: (a =  - 4) \\  \\  =  >  - 28 - 1 - 8 + 2 \\  \\  =  >  - 37 + 2 \\  \\  =  >  - 35 \\  \\  \\ b. \\  =  > 7a - 1 + 2a + 2 \\  \\  =  > 7a + 2a - 1 + 2 \\  \\  =  > 9a + 1 \\  \\  \\ c. \\  =  > 9a + 1 \\  \\  =  > 9( - 4) + 1 \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \: (a  =  - 4) \\  \\  =  >  - 36 + 1 \\  \\  =  >  - 35

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The mean of this data set is 9. What number is missing?<br><br> 11,20,_,3,1
kherson [118]
Let the missing number be x

Mean is the total sum of data over the number of data therefore,

(11+20+x+3+1) / 5 = 9
Then simplify
(35 + x) / 5 = 9
Then multiply 5 to both sides
35 + x = 45
Then subtract 35 to both sides to find x
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Hope this helps!

7 0
2 years ago
Rewrite the the expression using as few terms as possible. X^2+5x+4x+20
Effectus [21]

Answer:

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Step-by-step explanation:

x^2 + 5x + 4x + 20

x^2 + 9x + 20

all u have to do is combine liked terms

8 0
3 years ago
Suppose that two teams play a series of games that ends when one of them has won ???? games. Also suppose that each game played
Musya8 [376]

Answer:

(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0

(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0

Step-by-step explanation:

(a) when i = 2, the expected number of played games will be:

E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] =  4p²-4p+2-6p²+6p = -2p²+2p+2.

If p = 1/2, then:

d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.

(b) when i = 3;

E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]

Simplification and rearrangement lead to:

E(X) = 6p⁴-12p³+3p²+3p+3

if p = 1/2, then:

d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10

Therefore, E(X) is maximized.

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