Answer: 11 year
P(1) = 37,100
P(4) = 58,400
The linear equation (for x ≥ 1)
P(x) = 37,100 + a(x-1)
For x = 4
58,400 = 37,100 + a(4-1)
58,400 - 37,100 = 3a
21300 = 3a
a = 7100
So, the linear equation:
P(x) = 37100 + 7100*(x-1)
P(x) = 37100 + 7100x - 7,100
P(x) = 7100x + 30000
To find when the profit should reach 108100, we can substitute P(x) by 108100.
108100 = 7100x + 30000
108100 - 30000 = 7100x
78100 = 7100x
x = 78100/7100
x = 11
Answer: 11 year
We have that
<span>n (n-1) -4
for n=1
a1=1*(1-1)-4------> a1=-4
for n=2
</span>a2=2*(2-1)-4------> a2=-2
for n=3
a3=3*(3-1)-4------> a3=2
for n=4
a4=4*(4-1)-4------> a4=8
the answer is
-4,-2, 2, 8
Answer: 10 cups of sugar
Step-by-step explanation:
Cups of sugar : Cups of flour
2 : 3
? : 15
Cross multiply
3? = 15 × 2
3? = 30
Divide both sides by 3
? = 10
He needs 10 cups of sugar.
If the 3 is supposed to be replaced by any x's, then the answer would be 29 I believe.
