Answer:
hey there hope this answer helps you out
Step-by-step explanation:
we have two functions f(x) and g(x) such that
and
solving for f ° g, we'll substitute the x in f(x) by the value of g(x)
taking x common in denominator
for a function to exist it should not have 0 in its denominator
checking the values of x for which the denominator of f ° g becomes 0 :-
- x = 0 and
- x = -6
so the function doesn't exist at values x = 0, -6
<h3>So, <u>0, -6</u> cannot be in the domain of f°g</h3>
