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3 years ago

Write the number 110 as a sum of hundreds and tens

Mathematics

2 answers:

Nadya [2.5K]3 years ago

8 0

100+10.

Is that what you're asking for?

jarptica [38.1K]3 years ago

6 0

There's two answers since I don't really understand you're question ..

Either ⬇️ this

Hundreds - 100
Tens - 10
100+10=110

Or did u mean this ⬇️

There's one ☝️ 100 and one 10 so 1+1=2

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Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

What is the proper equation <br> (-5cd^-4)(2cd^2)^2

mojhsa [17]

Answer:

-20c^3

Step-by-step explanation:

((−5c)(d−4))((2cd2)2)

= −20c3d4 /d4

=-20c^3

7 0

3 years ago

Question: A square with sides of length 5 is positioned inside a square with sides of length 7. What is the total area between t

Sergio [31]

Answer:

The total area between the squares is of 24 units squared.

Step-by-step explanation:

Area of a square:

The area of a square of side length l is given by:

$A = l^2$

Area between figures:

The area between two figures is the area of the larger figure subtracted by the area of the smaller figure.

Larger square:

Square with side of length 7. So

$A_l = 7^2 = 49$

Smaller square:

Square with side of length 5. So

$A_s = 5^2 = 25$

What is the total area between the squares? 

$T = A_l - A_s = 49 - 25 = 24$

The total area between the squares is of 24 units squared.

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2 years ago

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LekaFEV [45]

Answer:

See below.

Step-by-step explanation:

A correct.

B correct.

C correct.

D correct.

E incorrect.

F correct.

G incorrect.

H correct.

I incorrect.

J incorrect.

K correctt.

-hope it helps

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2 years ago

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Vika [28.1K]

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3 years ago