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Andrei [34K]
3 years ago
15

-4 5/1 as a simplified fraction?

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
3 0
The answer is 1/1 or 1
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WILL GIVE A BRAINLEST!!!!!!
Andrej [43]
We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
 </span>- 1/(2-c)=-1/-(c-2)=1/(c-2)

(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2) 
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14

the solution is c=14
 
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or 
<span>all real numbers except c=-2 and c=2</span>


5 0
3 years ago
Read 2 more answers
Given the point (2,3) and the slope of 4 ,find y when x=22
Mariulka [41]
Y - y₁ = m(x - x₁)
 y - 3 = 4(22 - 2)
 y - 3 = 4(20)
 y - 3 = 80
   + 3  + 3
     y = 83
4 0
4 years ago
Read 2 more answers
Whats the volume of the composite shape ?​
otez555 [7]

Answer:

34 i think so i f it is wromg tell me

Step-by-step explanation:

3 0
4 years ago
What is the first step when rewriting y = 3x2 9x – 18 in the form y = a(x – h)2 k?
stiks02 [169]
A quadratic equation has the general form of: <span>

y=ax² + bx + c

It can be converted to the vertex form in order to determine the vertex of the parabola. It has the standard form of:

y = a(x+h)² - k

This can be done by completing a square. The steps are as follows:

</span><span>y = 3x2 + 9x – 18
</span>y = 3(x2 <span>+ 3x) – 18
</span>y + 27/4= 3(x2 <span>+ 3x+ 9/4) – 18 
</span>y = 3(x2 + 3/2)^2 – 99<span>/4
</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.
3 0
4 years ago
Read 2 more answers
Which of the following statements are true? Select all that apply.
Tom [10]

Answer: The statements in options 2 and 4 are true.

Explanation:

The LCM of two numbers is the smallest number that is multiple of both numbers.

The factor of 8 and 12 are,

8=2\times 2\times 2

12=2\times 2\times 3

Since 2 and 2 are common in both but 2 and 3 are not same, therefore the L.C.M. of 8 and 12 is,

L.C.M.(8,12)=2\times 2\times 2\times 3=24

Therefore the statement in option 1 is incorrect.

The factor of 6 and 9 are,

6=2\times 3

9=3\times 3

Since 3 is common in both but 2 and 3 are not same, therefore the L.C.M. of 6 and 9 is,

L.C.M.(6,9)=2\times 3\times 3=18

Therefore the statement in option 2 is correct.

The factor of 11 and 4 are,

11=1\times 11

4=2\times 2

Since all factor are different, therefore the L.C.M. of 11 and 4 is,

L.C.M.(11,4)=1\times 11\times 2\times 2=44

Therefore the statement in option 3 is incorrect.

The factor of 9 and 10 are,

9=1\times 9

10=2\times 5

Since all factor are different, therefore the L.C.M. of 9 and 10 is,

L.C.M.(9,10)=1\times 9\times 2\times 5=90

Therefore the statement in option 4 is correct.

4 0
3 years ago
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