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vovangra [49]
3 years ago
11

Rewrite 0.011 as a fraction in lowest terms

Mathematics
1 answer:
lions [1.4K]3 years ago
4 0

Answer:

11/1000 is the answer let me know if you need more help

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A box contains 5 plain pencils and 7 pens. A second box contains 4 color pencils and 4
Savatey [412]
5:7 (pencils to pens)

7/12 chance that a pen from the first box will be selected.

4:4 (colour pencils to crayons)

4/8 = 1/2 chance that a crayon from the second box will be selected.

The probability of picking both:

7/12 * 1/2 = 8/24 = 1/3



3 0
3 years ago
The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:
deff fn [24]

Step-by-step explanation:

Given equation of circle is,

{x}^{2}  +  {y}^{2}  - 6y - 12 = 0 \\ by \: compairing \: it \: with \:   \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f=  - 6 \\ or \: f=  - 3 \\ c =  - 12

again the another form of circle is,

{x}^{2}  +  {(y - k)}^{2}  = 21 \\ or \:  {x}^{2}  + {y}^{2}  - 2ky +  {k}^{2}  - 21 = 0 \\ by \: compairing \:it \: with \:  \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get  \\ g = 0 \\f =  - k \\ c =  {k}^{2}  - 21

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0
4 years ago
At summer camp, campers were asked to name their favorite sport. The circle graph shows the percent of campers who preferred eac
vladimir1956 [14]

I would say 260

Hope I helped

:)

5 0
3 years ago
Read 2 more answers
The total scores on the Medical College Admission Test (MCAT) in 2013 follow a Normal distribution with mean 25.3 and standard d
Elden [556K]
In a normal distribution, the median is the same as the mean (25.3). The first quartile is the value of Q_1 such that

\mathbb P(X

You have

\mathbb P(X

For the standard normal distribution, the first quartile is about z\approx-0.6745, and by symmetry the third quartile would be z\approx0.6745. In terms of the MCAT score distribution, these values are

\dfrac{Q_1-25.3}{6.5}=-0.6745\implies Q_1\approx20.9
\dfrac{Q_3-25.3}{6.5}=0.6745\implies Q_3\approx29.7

The interquartile range (IQR) is just the difference between the two quartiles, so the IQR is about 8.8.

The central 80% of the scores have z-scores \pm z such that

\mathbb P(-z

That leaves 10% on either side of this range, which means

\underbrace{\mathbb P(-z

You have

\mathbb P(Z

Converting to MCAT scores,

-1.2816=\dfrac{x_{\text{low}}-25.3}{6.5}\implies x_{\text{low}}\approx17.0
1.2816=\dfrac{x_{\text{high}}-25.3}{6.5}\implies x_{\text{high}}\approx33.6

So the interval that contains the central 80% is (17.0,33.6) (give or take).
7 0
3 years ago
Lawrence is making 10 gift baskets. The table shows the food he has bought for the baskets . if the food it divided evenly , how
IrinaVladis [17]

Answer:

i cant awnser

Step-by-step explanation:

wheres the table....like i cant tell

3 0
2 years ago
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