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3 years ago

A box contains 5 plain pencils and 7 pens. A second box contains 4 color pencils and 4

1 answer:

3 0

5:7 (pencils to pens)

7/12 chance that a pen from the first box will be selected.

4:4 (colour pencils to crayons)

4/8 = 1/2 chance that a crayon from the second box will be selected.

The probability of picking both:

7/12 * 1/2 = 8/24 = 1/3

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Completely lost ! Need Help With This !

Anettt [7]

80/5=16 cookies need 1 cup of flour
144/16= 9 cups to make 144 cookies

8 0

3 years ago

Find the area of a circular pond having radius Ans: 616 m 14 m.

krek1111 [17]

Step-by-step explanation:

Area of circular pond=22/7×14×14

=22/7×196

=616m

3 0

2 years ago

Suppose the null hypothesis is not rejected. State the conclusion based on the results of the test. Three years ago, the mean p

Likurg_2 [28]

Answer:

A. There is not sufficient evidence to conclude that the mean price of a single-family home has decreased

Step-by-step explanation:

To study : Whether the mean price of single family home has decreased or not -

Null Hypothesis [H0] = There is no change in mean price of single family home

Alternate Hypothesis [H1] = There is change (decrease) in mean price of single family home

If the null hypothesis is not rejected, it implies that 'there is no change in mean price of single family home' has been statistically accepted.

So, it states that - There is not sufficient evidence to conclude that the mean price of a single-family home has decreased

6 0

3 years ago

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 9090% of all males. (Accommodating 1

Molodets [167]

Answer:

Hip breadths less than or equal to 16.1 in. includes 90% of the males.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.5

Standard Deviation, σ = 1.2

We are given that the distribution of hip breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.10.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 14.5}{1.2})=0.10$

$= 1 -P( z \leq \displaystyle\frac{x - 14.5}{1.2})=0.10$

$=P( z \leq \displaystyle\frac{x - 14.5}{1.2})=0.90$

Calculation the value from standard normal z table, we have,

$P(z < 1.282) = 0.90$

$\displaystyle\frac{x - 14.5}{1.2} = 1.282\\x = 16.0384 \approx 16.1$

Hence, hip breadth of 16.1 in. separates the smallest 90% from the largest 10%.

That is hip breaths greater than 16.1 in. lies in the larger 10%.

4 0

3 years ago

How do I simplify 1/-5z^-5?

belka [17]

$\bf \cfrac{1}{-5z^{-5}}\\\\
-------------------------\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
% negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\
-------------------------\\\\
thus
$

$\bf -\cfrac{1}{5}\cdot \cfrac{1}{z^{-5}}\implies -\cfrac{1}{5}\cdot \cfrac{1}{\frac{1}{z^5}}\implies -\cfrac{1}{5}\cdot \cfrac{\frac{1}{1}}{\frac{1}{z^5}}\implies -
\cfrac{1}{5}\cdot \cfrac{1}{1}\cdot \cfrac{z^5}{1}
\\\\\\
-\cfrac{z^5}{5}$

3 0

3 years ago