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Yuri [45]
3 years ago
12

Kevin had $20. He bought a pen with 15% a notebook with 20% and a paintbrush with 8% how much money is left. EXPLAIN (TEST CORRE

CTIONS )
Mathematics
1 answer:
ira [324]3 years ago
8 0
The total % of $20 is 43% which is $3.6
$20-$3.6 = $16.4
There is $16.4 left
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Equal set is equivalent set but equivalent set not need equal set? why​
nasty-shy [4]
Equal sets have the exact same elements, so they must have the same number of elements. Therefore, equal sets must also be equivalent. No, not all equivalent sets are also equal sets
6 0
3 years ago
Sandy made 8 friendship bracelets she gave 1 bracelet to her best friend and 5 to to her friends in the tennis team
Oduvanchick [21]

Answer:

2

Step-by-step explanation:

1/8 2/8 3/8 4/8 5/8 6/8 7/8 8/8

8/8-6/8=2/8

8 0
4 years ago
Find an ordered pair that is a solution to the equation.
AveGali [126]

Answer:

(x,y) = (4,1)

Step-by-step explanation:

-4+5\cdot 1 = 5-4 =1

3 0
2 years ago
Read 2 more answers
Given the two sets, what is A ∩ B ? <br><br> A = {1, 2, 3, 4, 5, 6}<br><br> B = {2, 3, 5, 7}
topjm [15]

Answer:

2, 3, 5

Step-by-step explanation:

A∩B means "A intersection B" which includes all elements that are shared in BOTH sets. This would be the middle crossover section of a Venn diagram.

Hence, 2 and 3 and 5 are shared in both sets.

5 0
3 years ago
Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

3 0
3 years ago
Read 2 more answers
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