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hammer [34]
3 years ago
5

PLEASE HELP ITS FOR A TEST I WILL GIVE U BRAINLIEST

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer:

At the average rate of making profit, it will take slightly more than 30 hours for the business to reach a profit goal of $500. (30.075)

Step-by-step explanation:

a) It is not clear what linear equation is desired. We are given enough information to write an equation relating the number of bracelets produced by each worker to the time it takes.

Let n represent the number of bracelets Danica produces. Let r represent the number of bracelets Darrelle produces. Let h represent time in hours.

.. r/3 = h/4 ... Darrelle produces 3 bracelets in 4 hours

.. 4r - 3h = 0 ... equation in standard form

.. r = (3/4)h ... equation in slope-intercept form (the intercept is 0)

.. n/5 = h/2 ... Danica produces 5 bracelets in 2 hours

.. 2n - 5h = 0 ... equation in standard form

.. n = (5/2)h ... equation in slope-intercept form

b) We have no idea what special functions were discussed in the course. Of course these equations can be graphed. (2-dimensional equations are easily graphed.)

c) A profit function can be written in terms of the number of bracelets produced. Then it can be solved to find when (h=?) profit is equal to $500.

.. Let p represent the total profit from production of bracelets.

.. p = 10.50*r + 3.50*n ... profit in terms of bracelets produced

.. p = 10.50*((3/4)h) + 3.50*((5/2)h) ... profit in terms of hours, where both work the same hours

.. p = 16.625 h

.. 500 = 16.625 h ... we want to find hours until $500 profit

.. 500/16.625 = h ≈ 30.0752

At the average rate of making profit, it will take slightly more than 30 hours for the business to reach a profit goal of $500.

_____

If you work out the timing of when bracelets are finished, assuming they are made at a constant rate, you find that there will be 23 of Darrelle's bracelets and 76 of Danica's bracelets finished in 30 hours and 40 minutes. These will yield a profit of $507.50. After another 8 minutes, Danica will have finished bracelet 77 to add another $3.50 to the profit total.

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Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

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(divide by -4 on both sides)
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A) z value =  (x - π) / <span>σ   = 100 - 133 /  23  =  -1.43
p(<= 100) = 0.0764

</span>
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