<span>The two points that are most distant from (-1,0) are
exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3)
approximately (0.3333333, 1.885618) and (0.3333333, -1.885618)
Rewriting to express Y as a function of X, we get
4x^2 + y^2 = 4
y^2 = 4 - 4x^2
y = +/- sqrt(4 - 4x^2)
So that indicates that the range of values for X is -1 to 1.
Also the range of values for Y is from -2 to 2.
Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis.
So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So
y = sqrt(4-4x^2)
distance is
sqrt((x + 1)^2 + sqrt(4-4x^2)^2)
=sqrt(x^2 + 2x + 1 + 4 - 4x^2)
=sqrt(-3x^2 + 2x + 5)
And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving
-3x^2 + 2x + 5
Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative.
d = -3x^2 + 2x + 5
d' = -6x + 2
And set d' to 0 and solve for x, so
0 = -6x + 2
-2 = -6x
1/3 = x
So the furthest point will be where X = 1/3. Calculate those points using (1) above.
y = +/- sqrt(4 - 4x^2)
y = +/- sqrt(4 - 4(1/3)^2)
y = +/- sqrt(4 - 4(1/9))
y = +/- sqrt(4 - 4/9)
y = +/- sqrt(3 5/9)
y = +/- sqrt(32)/sqrt(9)
y = +/- 4sqrt(2)/3
y is approximately +/- 1.885618</span>
Answer:
D) -30x^2 -64x -18
Step-by-step explanation:
Given:
f(x) = 6x +2 and g(x) = -5x - 9
f(x).g(x) = (6x + 2) (-5x - 9)
Use distributive property
= 6x(-5x -9) + 2(-5x - 9)
= -30x^2 - 54x - 10x -18
= -30x^2 -64x - 18
Answer: d) -30x^2 -64x -18
Thank you.
Answer:
15 gallons
Step-by-step explanation:
Given that:
Pumping rate is modeled by the equation :
Q(t)=45-t gallons per minute ; where t is in minutes
Number of gallons in tank after 30 minutes ;
Q(t)=45-t
Q(30) = 45 - 30
Q(30) = 15
Hence, Number of gallons in tank after 30 minutes is 15 gallons
Answer:
0.125 is the answer...........
