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makvit [3.9K]
3 years ago
14

i think of a number. if i divide the sum of 6 and the number by 3, the result is 4 more than one quarter of the number. find the

number
Mathematics
2 answers:
slega [8]3 years ago
6 0

Answer:

-12

Step-by-step explanation:

Let the number be A

Given if you divide the sum of six and the number A by 3 , the result is 4 more than 1/4 of A

That’s

6+A/3 = 4+1/4 of A

6+A/3 = 4+1/4 x A

6+A/3 = 4+A/4

Cross multiply

4(6 + A) = 3(4 + A)

Distribute

4 x 6 + 4 x A = 3 x 4 + 3 x A

24 + 4A = 12 + 3A

Subtract 24 from both sides to eliminate 24 on the left side

24 - 24 + 4A = 12 - 24 + 3A

4A = -12 + 3A

Subtract 3A from both sides so the unknown can be on one side

4A - 3A = -12 + 3A - 3A

A = -12

Check

6+(-12)/3 = 4 +(-12)/4

6 -12/3 = 4 -12/4

-6/3 = -8/4

-2 = -2

mojhsa [17]3 years ago
6 0

Answer: 24

Step-by-step explanation:

(6+x)/3=0.25x+4

6+x=(0.25x+4)(3)

6+x=0.75x+12

x-0.75x=12-6

0.25x=6

x=6/0.25

x=24

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Part 2) f(x)=\frac{x}{x+4} ----> x\neq -4

Part 3)  f(x)=x(x+4) ----> All real numbers

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Step-by-step explanation:

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Part 1) we have

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The function is defined by all the values of x

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Part 4) we have

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we know that

In a quotient the denominator cannot be equal to zero

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Equate the denominator to zero

x^2+8x+16=0

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(x+4)^2=0

The solution is x=-4

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For the value of x=-4 the function is not defined

therefore

The domain is

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6 0
3 years ago
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