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Ivan
3 years ago
8

A restaurant receives a shipment of

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Subtract the amount used from the total packets:

5000 - 1824 = 3176 left after the first week.

3176 - 2352 = 824 total packets left.

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| 19) -6.5<br> What is the answer
Rashid [163]

Answer:

the answer will be 3.5 i think

Step-by-step explanation:

8 0
3 years ago
Which statement holds true for a skewed histogram showing a distribution of the weights of students in a class?
Papessa [141]
A is it and that might help


3 0
3 years ago
Read 2 more answers
The black figure is an ellipse, and the black line segment is is major axis. What is the length of the blue line segment?
NeTakaya

Answer:

D

Step-by-step explanation:

The formula we need to solve this is:

d_1+d_2=2a

Where

d_1  is the distance from one focus to the vertex

d_2  is the second distance from another focus to same vertex

<u>Note:</u> Here, vertex point is the point on top. The common point from which the RED and BLUE line meets the 2 foci

a  is half the length of the major axis (which is 9 here since total major axis is given as 18)

<em>Now we can plug into the equation and solve:</em>

<em>d_1+d_2=2a\\8.5+d_2=2(9)\\8.5+d_2=18\\d_2=18-8.5\\d_2=9.5</em>

<em />

<em>D is the correct answer.</em>

6 0
3 years ago
Find two integers whose sum -7 and whose product is 12
denpristay [2]
So we factor 12
remember that (-) times (-)=(+)
and
(-)+(-)=(-) so therefor the factors must be negative
factor 12
2,2,3

we have
-2 times -6 which adds to -8
-3 times -4 wihch adds to -7

the numbers are -3 and -4
7 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
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