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2 years ago

10

What is the quotient of b^3+4b^2-3b+126/b+7

1 answer:

stepladder [879]2 years ago

7 0

The correct answer for the question that is being presented above is this one: "D. b² − 3b + 18 R252. T<span>he quotient of b^3+4b^2-3b+126/b+7. In order to get the answer, you have to start dividing b^3 by b. Then multiply the quotient to b + 7. Then after that, subtract. Do the same thing until you reached the end.</span>

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3 years ago

What is the slope of the line represented by the equation 3x+2y=6?

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3 years ago

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The sum of two numbers is twelve. One number is eight less than the other. Find the numbers.

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3 years ago

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3 years ago

Find the measure of an angle whose supplement is six times its complement. Hint: The supplement and complement of an angle are (

sveticcg [70]

Let us translate the statements in the problem to mathematics equations

Let the angle is x degree

So its supplement is

$180^{\circ}-x$

And its complement is

$90^{\circ}-x$

Since the supplement is 6 times its complement, so Multiply the complement by 6 and equate the answer by the supplement

$180-x=6(90-x)$

Let us simplify the right side

$180\text{ - x = 6(90) - 6(x)}$ $180\text{ - x = 540 - 6x}$

Now let us solve the equation to find x

At first, add 6x to both sides to put x in the left side

$\begin{gathered} 180\text{ - x + 6x = 540 - 6x + 6x} \\ 180\text{ + 5x = 540} \end{gathered}$

Now subtract 180 from both sides to put the number in the right side

$\begin{gathered} 180\text{ - 180 + 5x = 540 - 180} \\ 5x\text{ = 360} \end{gathered}$

Divide both sides by 5 to get x

$\begin{gathered} \frac{5x}{5}=\frac{360}{5} \\ x=72^{\circ} \end{gathered}$

So the measure of the angle is 72 degrees

You can check the answer

180 - 72 = 108

90 - 72 = 18

18 * 6 = 108

So the supplement of 72 is six times its complement

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8 months ago