Answer:
Confidence interval = (4.61972, 25.46428)
Margin of Error = 3.9078675
Step-by-step explanation:
Given that :
This year:
Mean (μ1) = 64
Standard deviation (s1) = 13.8
Sample size (n1) = 28
Last year:
Mean (μ2) = 48.958
Standard deviation (s2) = 15.4
Sample size (n2) = 28
99% confidence interval estimate of the difference μ1−μ2
α = 1 - 99% = 0.01
(μ1−μ2) ± t0.01,27 * (√s1²/n1 + s2²/n2)
t0.01, 27 = 2.770683 (t value calculator)
√s1²/n1 + s2²/n2 = √13.8^2/28 + 15.4^2/28 = 3.9078675
(64 - 48.958) ± 2.667(3.9078675)
15.042 ± 10.42228
(15.042 - 10.42228), (15.042 + 10.42228)
(4.61972, 25.46428)
The margin of error :
√(s1²/n1) + (s2²/n2)
√(13.8^2/28) + (15.4^2/28)
√(6.8014285 + 8.47)
√15.2714285
= 3.9078675
Answer:
The answer is 400 :)
Step-by-step explanation:
hope that helped a little
x=4
Step-by-step explanation:
2x+4=12
-4 -4
---------------
2x = 8
---- ---
2 2
x=4
Answer:
<h3>1/4</h3>
Step-by-step explanation:
Given
amount of salamanders, = 5
amount of crayfish = 3
amount of minnows = 12
Total fish = Total outcome = 5+3+12
Total outcome = 20
Since we are looking for the probability of selecting salamanders, our expected outcome will be 5.
Probability = expected outcome/total outcome
Pr( salamanders,) = 5/20
Pr( salamanders) = 1/4
Hence the probability of selecting salamanders, is 1/4
