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borishaifa [10]
3 years ago
11

An item is regularly priced at $80 . It is on sale for 20% off the regular price. How much (in dollars) is discounted from the r

egular price?
Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0

80 * .20=16

It is 16 dollars off the regular price


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To get the answer, divide 3852 feet by 4 days. That will give you an average of 963 feet per day as your answer.
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PLEASEE HEEELP! In the normal distribution, 68% of the data lies within 1 standard deviation A: __/6 of the mean, 95% of the dat
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Answer:

a) 2.5% b) 50%

Step-by-step explanation:

1300 is two standard deviations higher than the mean. Since 95% of the data is covered within two standard deviations to the left and right of the mean, 5% is not covered. So, we have 2.5% leftover on the left side of the curve, under 900, and 2.5% leftover on the right side of the graph that is above 1300.

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A researcher claims that the average body mass index (BMI) of adult Canadians is more than 25.0. He takes a SRS of 250 Canadians
Serjik [45]

Answer:

The probability of obtaining a result equivalent to or greater than what was the truly observed value of the test statistic is 0.001.

Step-by-step explanation:

The researcher can use a one sample <em>z</em> test to determine whether his claim is correct or not.

The hypothesis to test whether the mean BMI is more than 25.0, is defined as:

<em>H₀</em>: The mean BMI is not more than 25.0, i.e. <em>μ </em>≤ 25.0.

<em>Hₐ</em>: The mean BMI is more than 25.0, i.e. <em>μ </em>> 25.0.

The test statistic is defined as:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}

The <em>p</em>-value of the test is,

<em>p</em> = 0.001.

The p-value is well-defined as per the probability, [under the null-hypothesis (<em>H₀</em>)], of attaining a result equivalent to or greater than what was the truly observed value of the test statistic.

A small p-value (typically ≤ 0.05) specifies sufficient proof against the null hypothesis (<em>H₀</em>), so you discard <em>H₀</em>. A large p-value (> 0.05) specifies fragile proof against the <em>H₀</em>, so you fail to discard <em>H₀.</em>

The <em>p</em>-value of 0.001 indicates that the probability of obtaining a result equivalent to or greater than what was the truly observed value of the test statistic is 0.001.

As the <em>p</em>-value is very small, the null hypothesis will be rejected at any level of significance.

Thus, concluding that the mean BMI of adult Canadians is more than 25.0.

3 0
3 years ago
A number y is 6 less than twice a number
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Answer:

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7 0
3 years ago
Help solving this math question
olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = \frac{488,106,000-358,708,000}{2} = \frac{129,398,000}{2} = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = \frac{4,051,050}{5,921,379} = 0.6841,

Agricultural / natural resources ratio = \frac{373,904}{488,106} = 0.766,

Education's ratio = \frac{2,164,607}{3,008,036} = 0.7196,

General government's ratio = \frac{14,347,325}{14,716,155} = 0.9749,

Highways and transportation's ratio = \frac{1,468,482}{1,773,893} = 0.827,

Public safety's ratio = \frac{263,463}{464,233} = 0.5675.

The Human resources' program ratio is 0.6841 and the closest is Education's ratio which is 0.7196. So education is the answer.

4 0
2 years ago
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