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yanalaym [24]
3 years ago
6

Help Please This Is a bit hard so I will give Brainliest if Correct!!

Mathematics
1 answer:
Goshia [24]3 years ago
7 0

Answer:

125 to the 6th power.

Step-by-step explanation:

2 * 3 * 125 = 750

plz give brainly.

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Mary is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect? Which coordinates if they do? Negat
Umnica [9.8K]

Answer:

The graphs of the two function will not intersect.

Step-by-step explanation:

We are given a quadratic function f(x).

Also g(x) is given by a set of values as:

 x            g(x)

 1              -1

  2             0

  3              1

As g(x) is a linear function hence we find out the equation of g(x) by the slope intercept form of a line: y=mx+c

let g(x)=y

when x=1 ,   g(x)=-1

-1=m+c----(1)

when x=2   , g(x)=0

0=2m+c------(2)

Hence, on solving (1) and (2) by method of elimination we get:

m=1 and c=-2

Hence, the equation of g(x) is:

g(x)=x-2

So clearly from the graph we could see that the graph of the two functions will never intersect.


3 0
3 years ago
Read 2 more answers
What do you say about the proposition "4 divides n" compared to the proposition "2 divides n"?
likoan [24]

Answer:

добре звучи добре

Step-by-step explanation:

7 0
2 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP ITS OVERDUE PLEASE I NEED HELP!!
IgorLugansk [536]

Answer:

First question: Choice A

second question:Choice D

Third question: Choice c

Fourth question: Choise b

5th Question: choice b

5 0
2 years ago
Can someone PLEASE help me with this problem?
Novay_Z [31]

Answer:

3/5 of a foot

Step-by-step explanation:

1/5+2/5=3/5

5 0
2 years ago
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