Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
3.6x - 2y = 6
-2.7x + y = 3.....multiply by 2
----------------
3.6x - 2y = 6
-5.4x + 2y = 6 (result of multiplying by 2)
----------------add
-1.8x = 12
x = 12/-1.8
x = - 6.67 (or -20/3)
3.6x - 2y = 6
3.6(-6.67) - 2y = 6
-24.01 - 2y = 6
-24.01 - 6 = 2y
-30.01 = 2y
-30.01 / 2 = y
-15 = y
solution : (-6.67, -15)
<span>2x(x2 + 2x - 6)
</span>First add what is in the "(" wich is 2x+2x
<span>2x(4x - 6)
</span>Second multiply the 2x by the 4x & -6
<span>8x-12x
Now subtract the -12x from the 8x
8x-12x = -4x
</span>
Answer:
18
Step-by-step explanation:
I did that in my head could be wrong
