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MaRussiya [10]
2 years ago
10

All of the following expressions are equivalent to 12w + 6, except:

Mathematics
2 answers:
larisa [96]2 years ago
7 0

Answer:

-1 (12w-6)

Step-by-step explanation:

the original equation does have the 12 negative.

laiz [17]2 years ago
5 0
-1(12w - 6) is not equivalent because when the -1 is distributed, the equation becomes -12w + 6, not 12w + 6
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Rewrite the expression by favoring out the greatest common factor: 9b+12
malfutka [58]

Answer:

3(3b + 4)

the GCF is 3

Step-by-step explanation:

7 0
3 years ago
Suppose a parabola has an axis of symmetry at x=-5, a maximum height of 9, and passes through the point (-7,1). Write the equati
Nutka1998 [239]

the parabola has maximum at 9, meaning is a vertical parabola and it opens downwards.

it has a symmetry at x = -5, namely its vertex's x-coordinate is -5.

check the picture below.

so then, we can pretty much tell its vertex is at (-5 , 9), and we also know it passes through (-7, 1)


\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9


\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill

7 0
3 years ago
Fine the product:3 x 5 (2)
Delvig [45]

Answer:

30 because 3 x 5=15 then x2 it's 30

3 0
3 years ago
Subtract 65 from the product of 20 and 4.​
Klio2033 [76]

Answer:

15 is the answer

Step-by-step explanation:

20×4=80

80-65=15

3 0
2 years ago
Read 2 more answers
Whats 4 + 2 i forgot,<br> and whats 5 + 5 + 9 + 8 + 90+ 90 - 1000 i also forgot
Vlad [161]

Answer:

4 + 2 = 6

5 + 5 + 9 + 8 + 90+ 90 - 1000 = -793

Step-by-step explanation:

hope this helps ;)

have a great day!! <3

8 0
3 years ago
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