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3 years ago

Solve for x and y. And please explain

Mathematics

1 answer:

pishuonlain [190]3 years ago

5 0

These are called same side interior angles.
They equal 180°.
1. 3x-7+4x-9=180
2. 7x-16=180
3. 7x=196
4. x=28

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Solve the whole problem i give brainliest please help me.

Anna11 [10]

Answer:

The inequality is 12.5v + 70 ≥ 215

and the amount of visits they can make is 12 visits

Step-by-step explanation:

if you take away (subtract) 70 from both sides, you'll get

12.5v ≥ 145

and when you divide both sides by 12.5, you'll get 11.6, or 12

3 0

3 years ago

4x + y = 7 3x + 2y = 9

Diano4ka-milaya [45]

Answer:

x = 1

y = 3

Step-by-step explanation:

<h2>Substitution Method:</h2>

Step 1:

Name The Equation

4x + y = 7 ...(1)

3x + 2y = 9 ...(2)

Step 2:

From Equation (1) we get,

4x = 7 - y

i.e.,

x = 7 - y/4

Step 3:

Substitute the value of x = 7 - y/4 in equation (2)

i.e.,

3(7 - y/4) + 2y = 9

21 - 3y/4 + 2y = 9

21 - 3y + 8y/4 = 9

21 - 3y + 8y = 9 * 4

21 + 5y = 36

5y = 36 - 21

5y = 15

y = 15/5

y = 3

Step 4:

Substitute the value of y = 3 in equation (1)

4x + y = 7

i.e.,

4x + (3) = 7

4x + 3 = 7

4x = 7 - 4

4x = 4

x = 4/4

x = 1

<h2>Verification: </h2>

4x + y = 7 i.e., 4(1) + (3) = 7

3x + 2y = 9 i.e., 3(1) + 2(3) = 9

3 0

3 years ago

I need help answering these questions for geometry :)

iren2701 [21]

The answers to the question have been written below

<h3>The changes to a polygon</h3>

1. If the number of sides of the polygon should increase then the measure of the interior angle would increase by 180.

2. A regular polygon has the sum of its external angles as 360. This is solved as 360/n = 0

Hence the value of the exterior would move towards 0 as its sides increases.

4. As the total sum of the of the polygon changes, it would tend towards infinity.

5. The total sum of the exterior angles as the number of sides changes would tends towards 360 degrees.

Read more on polygon here:

brainly.com/question/1592456

#SPJ1

8 0

2 years ago

When the sum of 5 and three times a positive number is subtracted from the square of the number, 0 results. Find the number.

Juliette [100K]

$x-the\ number\\\\x^2-(5+3x)=0\\\\x^2-5-3x=0\\\\x^2-3x-5=0$

$Use\ the\ quadratic\ formula:\\a^2x+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta > 0\ then\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\if\ \Delta=0\ then\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta < 0\ then\ no\ solution$

$x^2-3x-5=0\\\\a=1;\ b=-3;\ c=-5\\\\\Delta=(-3)^2-4\cdot1\cdot(-5)+3+20=29 \ \textgreater \ 0\\\\\sqrt\Delta=\sqrt{29}\\\\x_1=\dfrac{3-\sqrt{29}}{2\cdot1}=\dfrac{3-\sqrt{29}}{2} \ \textless \ 0\\\\x_2=\dfrac{3+\sqrt{29}}{2\cdot1}=\dfrac{3+\sqrt{29}}{2} \ \textgreater \ 0$

$Answer:\ \boxed{x=\dfrac{3+\sqrt{29}}{2}}$

6 0

3 years ago

the probability density for a particle in a box is an oscillatory function even for very large energies. Explain how the classic

77julia77 [94]

Answer:

This is achieved for the specific case when high quantum number with low resolution is present.

Step-by-step explanation:

In Quantum Mechanics, the probability density defines the region in which the likelihood of finding the particle is most.

Now for the particle in the box, the probability density is also dependent on resolution as well so for large quantum number with small resolution, the oscillations will be densely packed and thus indicating in the formation of a constant probability density throughout similar to that of classical approach.

8 0

3 years ago