Answer: 294√3
Explanation:
1) The described hexagon has these featrues:
a) 6 congruent equilateral triangles whose side lengths measure 14
b) height of each triangle = apotema = a
c) the area of each triangle is base × a / 2 = 14 × a / 2 = 7a
2) a is one leg of a right triangle whose other leg is 14 / 2 = 7, and the hypotenuse is 14.
3) Then you can use Pythagorean theorem fo find a:
14² = 7² + a² ⇒ a² = 14² - 7² = 147 ⇒ a = √ 147 = 7√3
4) Therefore, the area of one triangle is: 14 × 7√3 / 2 = 49√3
5) And the area of the hexagon is 6 times that: 6 × 49√3 = 294√3
Answer:
x ≈ 5.89
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra II</u>
- Exponential to Logarithmic:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
0.77 = log(x)
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Equality Property] Raise both sides to the 10th power:

- Simplify:

- Evaluate:

293764 would be the answer to this question
2 hours and a half, or 2 hours and 30 minutes. :-)