The radius of the cylindrical vase is 8 centimeters, if the cylindrical vase holds 8,038.4 cubic centimeters of water and the height of the vase is 40 centimeters.
Step-by-step explanation:
The given is,
Volume of cylindrical vase = 8038.4 cubic centimeters
Height of the cylindrical vase = 40 centimeters
Step:1
Formula for volume of cylindrical vase,
......................(1)
Where, r - Radius of cylindrical vase
h - Height of cylindrical vase
From the given,
V = 8038.4 cubic centimeters
h = 40 centimeters
Equation (1) becomes,
8038.4 
(∵ 
= 3.14 )
r = 8 centimeters
Result:
The radius of the cylindrical vase is 8 centimeters, if the cylindrical vase holds 8,038.4 cubic centimeters of water and the height of the vase is 40 centimeters.
Answer:
Step-by-step explanation:
y
=
m
x
+
b
y
=
3
/4
x
−
8
Rewrite in slope-intercept form.
y
=
3
/4
x
−
8
Using the slope-intercept form, the slope is 3
/4
.
m
=3
/4
To determine how far away Oscars grandpa lives you would need to divide 50 by 6. 50/6= 8 and 1 third, or 8.33
There are two possibilities, and we don't know which situation is true.
<em>#1).</em> School is in the middle, between home and grandparents.
Home --------- 3/8 ----------- School --------- 2/8 ------- Grandparents .
If this is true, then in the whole day, Tasha walks
(3/8 + 2/8 + 2/8 + 3/8) = 10/8 = <u>1.25 miles</u> .
===========================================
<em>#2):</em> Grandparents house is in the middle, between home and school.
Tasha passes by them on her way to school, and stops there to visit
on her way back home.
Home ------- 1/8 ------- Grandparents ---------- 2/8 ---------- School
If this is true, then in the whole day, Tasha walks
(3/8 + 2/8 + 1/8) = 6/8 = <u>3/4 mile</u> .
First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx
(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
