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3 years ago

Pleaseeee hELPppP correct answer

Mathematics

1 answer:

Elena-2011 [213]3 years ago

4 0

Answer:

I'm thinking HL.

Step-by-step explanation:

So, in order to be AAS, the angles have to be the next thing after each other if that makes sense. Like, for example, you could do triangle RSQ is congruent to triangle QPR IF S and P were congruent... but there not, darn! So! That isn't the answer. In order to do SAS, you would need lines RS and PQ to be congruent because they are back-to-back with angles R,Q, plus the side (leg) that the triangles share which automatically makes them congruent btw :) Okay so this is getting a little lengthy (sorry) but I just wanted to explain why some of the answers are automatic turn offs. Anyhoo, HL would work because the hypotenuses (QS and PR) are congruent along with the one leg that both triangles share (QR or RQ however you want to look at it). I'm sorry if I'm wrong. I hope this helps!! Good luck! and always remember, if the angles and sides aren't next to each other, it doesn't match up with SAS, AAS, SSS, or ASA. Have a good night!

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In tossing four fair dice, what is the probability of tossing, at most, one 3

11Alexandr11 [23.1K]

<u>Answer- </u>

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

<u>Solution-</u>

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

$P(A) =The \ probability \ of \ getting \ zero \ 3 =(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})=\frac{625}{1296} =0.48$ ( ∵ xxxx )

$P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)(\frac{1}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6}) = 0.38$ ( ∵ 3xxx, x3xx, xx3x, xxx3 )

P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86

7 0

3 years ago

Help 16-18 thank you

saw5 [17]

Answer:

16. (80)(60) = 4800

17. (500)(600) = 300000

18. (700)(800) = 560000 a). high

Step-by-step explanation:

5 0

3 years ago

find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho

____ [38]

For a quadratic of the form $f(x)=ax^2+bx+c$ , we have the quadratic formula
$x=\dfrac{-b \pm \sqrt{b^2 -4ac} }{2a}$ ,
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given $2x^2-16x+27=0$ , we can get that $a=2, \ b=-16$ , and $c=27$ . We substitute these numbers into the quadratic formula above.

$x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}$

$x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}$

$x=\dfrac{16 \pm \sqrt{40} }{4}$

$x=\dfrac{16 \pm 2\sqrt{10} }{4}$

$x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}$

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the $\pm$ symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.

8 0

3 years ago

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bixtya [17]

Answer:

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Step-by-step explanation:

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5 0

3 years ago

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finlep [7]

Answer:

Step-by-step explanation:

8 0

3 years ago