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3 years ago

What fraction of a £1 is eighty pence

2 answers:

7 0

I think it would 80/100 because £1 is 100 and we trying to work out the fraction of 80p of £1. So it would be 80/100. Hope this helps.

tresset_1 [31]3 years ago

6 0

4/5
put it this way
80/100
half it= 40/50
then simplify it= 4/5
easy!

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Lena [83]

Answer:

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6 0

2 years ago

One number is larger than another by 9. If the greater number is increased by 10, and the lesser number is tripled, the sum of t

kkurt [141]

Answer:

The larger number is -6, the smaller number is -15

Step-by-step explanation:

We have two numbers, a and b.

We know that one number is larger than another by 9.

Then we can write:

a = b + 9

then a is larger than b by 9 units.

If the greater number is increased by 10 (a + 10) and the lesser number is tripled (3*b), the sum of the two would be -41:

(a + 10) + 3*b = -41

So we got two equations:

a = b + 9

(a + 10) + 3*b = -41

This is a system of equations.

One way to solve this is first isolate one variable in one of the two equations:

But we can see that the variable "a" is already isolated in the first equation, so we have:

a = b + 9

now we can replace that in the other equation:

(a + 10) + 3*b = -41

(b + 9) + 10 + 3*b = -41

now we can solve this for b.

9 + b + 10 + 3b = -41

(9 + 10) + (3b + b) = -41

19 + 4b = -41

4b = -41 -19 = -60

b = -60/4 = -15

b = -15

then:

a = b + 9

a = -15 + 9 = -6

a = -6

7 0

2 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

step 1

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

step 2

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Find the area of the larger circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

Jim, Carla and Tomy are members of the same family. Carla is 5 years older than Jim. Tomy is 6 years older than Carla. The sum o

Blizzard [7]

We are given these three people age below:

Jim's age
Carla's age
Tomy's age

We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.

Jim's age = x

Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.

Carla's age = x+5

Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).

Tomy's age = 6+(x+5)

The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.

$\large{x + x + 5 + 6 + x + 5 = 31}$

Combine like terms and solve for x.

$\large{3x + 16 = 31} \\ \large{3x = 31 - 16} \\ \large{3x = 15} \\ \large{x = 5}$

Then we substitute the value of x in ages to find these three people ages.

Jim's age = x = 5
Carla's age = x+5 = 5+5 = 10
Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.

Answer

Jim's age = 5
Carla's age = 10
Tomy's age = 16

4 0

3 years ago

When the outliers are removed how does the mean change? Dot plot with one on 18, 2 on 38, one on 40, 3 on 44, one on 46, one on

Vitek1552 [10]

18,38,38,40,44,44,44,46,48....
the mean with the outlier (18) included is : 360/9 = 40

38,38,40,44,44,44,46,48
the mean with the outlier (18) excluded is : (360 - 18) / 9 = 342/9 = 38

so when the outlier is removed, the mean is 2 points less

4 0

3 years ago

Read 2 more answers