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GrogVix [38]
3 years ago
7

Write the system of linear equations Y=3x+1 Y=2x+3

Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

x = 2

y =7

Step-by-step explanation:

the system of linear equation will be solve using substitution method,

let

Y=3x+1.............................................. equation 1

Y=2x+3.............................................. equation 2

substitute equation 1 into equation 2

3x + 1 = 2x + 3

combine the like terms

3x+1 -2x = 3

x = 3 -1

x = 2

put the value of x=2 in either equation 1 or 2

Y=2x+3.............................................. equation 2

y = 2(2) + 3

y = 4 + 3

y = 7

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A company ships coffee mugs using boxes in the shape of cubes. The function g(x) = gives the side length, in inches, for a cube
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Answer:

The graph is attached below.

Step-by-step explanation:

The volume of the box containing the coffee mugs is,

V=x^{3}

Then the function representing the side length, in inches, for the box is:

g(x)=x

Now, it is provided that the company decides to double the volume of the box.

That is, the new volume will be:

V_{n}=2x^{3}

Then the side length, in inches, for the box will be:

g_{n}(x)=\sqrt[3]{2x^{3}} =\sqrt[3]{2}x

Then the graph representing the function, formed using the following points is:

x\ \ \ \ \ \ \ \ \ g_{n}(x)\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\0\ \ \ \ \ \ \ \ \ \ \ 0\\1\ \ \ \ \ \ \ \ \ \ \ 2^{1/3}

3 0
3 years ago
Read 2 more answers
3(2+q) + 15 simplified
sasho [114]

Answer:

Rearrange terms

3(2+)+15

3({\color{#c92786}{2+q}})+153(2+q)+15

3(+2)+15

3({\color{#c92786}{q+2}})+153(q+2)+15

2

Distribute

3(+2)+15

{\color{#c92786}{3(q+2)}}+153(q+2)+15

3+6+15

{\color{#c92786}{3q+6}}+153q+6+15

3

Add the numbers

3+6+15

3q+{\color{#c92786}{6}}+{\color{#c92786}{15}}3q+6+15

3+21

3q+{\color{#c92786}{21}}3q+21

Solution

3+21

7 0
3 years ago
Karina needs a total score of at least 627 on three games of bowling to break the league record. Suppose she bowls 222 on her fi
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3 years ago
Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) - 6 = 0?
viva [34]
Answer:
The third option

Explanation:
The given expression is:
(x+2)² + 5(x+2) - 6 = 0

Let's check each of the given options:
1- Option A:
(u+2)² + 5(u+2) - 6 = 0
At u = x - 2, the expression would become:
(x-2+2)² + 5(x-2+2) - 6 = 0
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2- Option B:
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At u = x-2, the expression would become:
(x-2)²  + 5(x-2) - 2 = 0 ..........> This option is incorrect

3- Option C:
u² + 5u - 6 = 0
At u = x+2, the expression would become:
(x+2)² + 5(x+2) - 6 = 0 .........> This option is correct

4- Option D:
u² + u - 6 = 0
At u = x+2, the expression would become:
(x+2)² + (x+2) - 6 = 0 ..........> This option is incorrect

Hope this helps :)

3 0
3 years ago
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