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3 years ago

Please check my work

Mathematics

1 answer:

Andreyy893 years ago

5 0

Where is the work i dont see it

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At the gym, Jasper was able to bench press 224 pounds, which was 7/8 of the weight that Balin was able to bench press. Which sho

Rzqust [24]

Answer:

The answer SHOULD be 7/8=224/x;256 pounds.

You may have made a mistake in inputting it here on Brainly. So look for the one that matches that.

Step-by-step explanation:

This is what we know:

Jasper = 224 pounds

Balin = x

Jasper = 7/8 of x

Now we make an equation for that:

$(\dfrac{7}{8})(x) = 224pounds$

To match the selections we will isolate 7/8 on one side of the equation:

$\dfrac{7}{8}=\dfrac{224}{x}$

Using ratio and proportion we can solve for what x is. Multiply 224 by 8 and divide it by 7. Or you can do it this way too:

$\dfrac{7}{8}=\dfrac{224}{x}$

$(7)(x)=(224pounds)(8)$

$7x=1792pounds$

$x=\dfrac{1792pounds}{7}=256pounds$

So x = 256 pounds

7 0

3 years ago

Read 2 more answers

Can someone help lol

djverab [1.8K]

Answer:

p=30 q=150

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PLS HELP WILL GIVE BRANLIEST

BartSMP [9]

The answer is A if I am correct

3 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$