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Mandarinka [93]
3 years ago
9

Pleeeeeasssseeee heeeelppp!! File is attached!!

Mathematics
1 answer:
rjkz [21]3 years ago
4 0
3/10 -c
2/10-b
9/10- h
7/10-g
1/10-a
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Midpoint of the segment between the points (−5,13) and (6,4)
Leokris [45]

Answer: (0.5,8.5)

Step-by-step explanation:

We need to use the following formula to find the Midpoint "M":

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Given the points (-5,13) and (6,4) can identify that:

x_1=-5\\x_2=6\\\\y_1=13\\y_2=4

The final step is to substitute values into the formula.

Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:

M=(\frac{-5+6}{2},\frac{13+4}{2})\\\\M=(\frac{1}{2},\frac{17}{2})\\\\M=(0.5,8.5)

6 0
3 years ago
Read 2 more answers
Jaime has 38 marbles if Jorge had 14 more marbles he would have twice as many as Jaime how many marbles does Jorge have now?
Ganezh [65]

Answer:  Jorge has 62 marbles.

Step-by-step explanation:  Given that Jaime has 38 marbles if Jorge had 14 more marbles he would have twice as many as Jaime.

We are to find the number of marbles that Jorge has.

Let x and y represents the number of marbles that Jalme and Jorge has respectively.

Then, according to the given information, we have

x=38

and

y+14=2x\\\\\Rightarrow y+14=2\times38\\\\\Rightarrow y+14=76\\\\\Rightarrow y=76-14\\\\\Rightarrow y=62.

Thus, Jorge has 62 marbles.

5 0
3 years ago
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PLSSSSS HELPPPPPPP ASAPPPPPP!!!! I WILLL GIVE BRAINLIEST!!!!
ELEN [110]

Answer:

sure

Step-by-step explanation:

4 0
3 years ago
What is 4/9 and 17/18 renamed using least common denominator?
dusya [7]

Answer:

8/18 & 17/18 is your answer.

Step-by-step explanation:

Find common denominators for both (you cannot simplify). Note that what you do to the denominator, you must do to the numerator. Find multiples of each number:

9: 9, 18

18: 18

The first least common denominator you get is 18. Solve:

(4/9)(2/2) = 8/18

8/18 & 17/18 is your answer.

~

3 0
3 years ago
What’s the reciprocal of 5
Tanya [424]

Answer: 0.2

Step-by-step explanation:

8 0
3 years ago
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