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2 years ago

The number 75 falls netween what two perfect squares?

Mathematics

2 answers:

Alina [70]2 years ago

7 0

Answer:

8^2 and 9^2 which is also 64 and 61

Step-by-step explanation:

xeze [42]2 years ago

5 0

Answer:

75 is between 64 and 81.

Step-by-step explanation:

The number 75 falls between 64 and 81, which are both perfect squares.

To find out whether a number is a perfect square, we can take the square root of said number. If the answer is a whole number, then the number is a perfect square.

The square root of 64 is 8 and the square root of 81 is 9, so they are both perfect squares. We know that 75 is between the numbers 64 and 81, therefore our answer is correct.

Hope this helps!

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Answer:

Step-by-step explanation:

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2 years ago

Which number is irrational

alina1380 [7]

For this case, we have by definition, that an irrational number is a number that can not be expressed as a fraction $\frac {a} {b}$ , where a and b are integers and b is nonzero.

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3 years ago

1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat

brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

$x = 2$ is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) $f(x) = 6x + 6/x$

$f\prime(x) = 6 - 6/x^2 = 0$ and $x \neq 0$

So, the roots are $x = -1$ and $x = 1$

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum.

2) $f(x)=6-4/x+2/x^2$

$f\prime(x)=4/x^2-4/x^3=0$ and $x \neq 0$

So the root is $x = 1$

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum.

3) $f(x) = 8x^2/(x-4)$

$f\prime(x) = (8x^2-64x)/(x-4)^2=0$ and $x \neq 4$

So the roots are $x = 0$ and $x = 8$

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum.

4) $f(x)=6(x-2)^{2/3} +4=0$

$f\prime(x) = 4/(x-2)^{1/3}$ has no solution and $x = 2$ is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

$x = 2$ is absolute minimum.

5) $f(x)=8\sqrt x - 6x$ for $x>0$

$f\prime(x) = (4/\sqrt x)-6 = 0$

So the root is $x = 4/9$

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum.

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2 years ago

If the bottom row as a result of sythetic division is 1 3 0 4 0, then the quotient is which of the following? Select one:

zmey [24]

The quotient of the synthetic division is x^3 + 3x^2 + 4

<h3>How to determine the quotient?</h3>

The bottom row of synthetic division given as:

1 3 0 4 0

The last digit represents the remainder, while the other represents the quotient.

So, we have:

Quotient = 1 3 0 4

Introduce the variables

Quotient = 1x^3 + 3x^2 + 0x + 4

Evaluate

Quotient = x^3 + 3x^2 + 4

Hence, the quotient of the synthetic division is x^3 + 3x^2 + 4

Read more about synthetic division at:

brainly.com/question/18788426

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1 year ago

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Please help, we learned this today and I’m really confused. How do you do it?

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3 years ago

The number 75 falls netween what two perfect squares?​

The number 75 falls netween what two perfect squares?