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SOVA2 [1]
3 years ago
8

The amount of tax for another camera is $5.25 and the tax rate is 6%. Use the given equation to find the price before tax.

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0

Answer:

The price of the camera before tax would be $ 87.5.

Step-by-step explanation:

Let x be the price of the camera before tax,

Given,

The percentage of tax = 6 %,

So, the amount of tax = 6 % of the price before tax

= 6 % of x

= 0.06x

According to the question,

The amount of tax = $ 5.25

\implies 0.06x = 5.25

\implies x=\frac{5.25}{0.06}=87.5

Hence, the price of the camera before tax is $ 87.5.

olga_2 [115]3 years ago
3 0
$87.50x.06=$5.25 tax
so it's the tax ($5.25/0.06)
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Answer:

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Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

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15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

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4 years ago
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Step-by-step explanation:

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P(X = x) = \frac{y^xe^{-y}}{x!}

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<em />

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P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

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