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stealth61 [152]
3 years ago
6

The length of a rectangle is four times its width. If the perimeter is at most 100 centimeters, what is the greatest possible va

lue for the width?
Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0
P=2(L+W)
100≥P

L is 4 times W
L=4W
sub 4W for L

100≥2(4W+W)
100≥2(5W)
100≥10W
divide both sides by 10
10≥W

the greatest possible width is 10cm
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Answer:

x = 9.6

Step-by-step explanation:

Before we can figure out what x is, we need to figure out what the unlabeled side is. To figure that out, multiply the hypotenuse (12) by the sine of the angle labeled (34)

12 * sin(34)

<em>sin(34) equals 0.559192903470747; I'll round it to 0.6 for convenience.</em>

12 * 0.6

<em>Now simply multiply 12 by 0.6 to get 7.2.</em>

The unlabeled side is approx. 7.2 units long.

Now we know what the unlabeled side is. Now, to find x, find the square root of 12 squared minus 7.2 squared.

x = √12² - 7.2²

<em>12 squared is 144; 7.2 squared is 51.84.</em>

x = √144 - 51.84

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<em>The square root of 92.16 is 9.6 (on the spot!).</em>

x equals 9.6.

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