Answer and Step-by-step explanation:
Given that probability of you winning each game = 0.68
And probability of you winning next game = 0.81
Your friend's chance of winning/you losing would be = 1-0.68= 0.32
also his chance of winning next game = 0.73
To find probability that you would win the series given that you need to win two games to win the series
= probability that you win first game and second game+ probability that you win first game, lose second game and win third game + probability that you lose first game, win second game and win third game
= 0.68*0.81+0.68*0.32*0.68+0.32*0.68*0.81
=0.8750
Therefore probability that you would win the series = 0.8750
Note: here we found the probability of winning by adding(or) up the three possible combinations that would result in a win
Answer:
$2191.12
Step-by-step explanation:
We are asked to find the value of a bond after 10 years, if you invest $1000 in a savings bond that pays 4% interest, compounded semi-annually.
, where,
,
r = Rate of return in decimal form.
n = Number of periods.
Since interest is compounded semi-annually, so 'n' will be 2 times 10 that is 20.
Therefore, the bond would be $2191.12 worth in 10 years.
The one that is less because if you use more you wound have any later
<u>Solution</u> :
Let, the number be A
Given, A/2 + 12 = 6
⇒ (A + 24)/2 = 6
⇒ A + 24 = 12
⇒ A = 12 - 24
⇒ A = - 12
∴ the required number is (- 12). (Ans.)
28% of 1500 is 420.
so add it to 1500 and you’ll get 1920
