Answer:
y= -4x-7 or 4x+y= -7
Step-by-step explanation:
we know y=mx+c
given,
m=-4 c=-7
the equation y= -4x-7 or 4x+y= -7
thank u
Answer:
wouldnt it be (6,-1)...
Step-by-step explanation:
because those are the cords your said c was at
Chain rule
y=f(g(x))
y´=(d f(gx)/d g)(d g/d x)
or
y=y(v) and v=v(x), then dy /dx=(dy/dv)(dv/dx)
in our case:
y=sin (v)
v=arcsin(x)
dy/dv=d sin (v)/dv=cos (v)=cos(arcsin(x)
dv/dx=d arcsin(x)/dx=1/√(1-x²)
dy/dx=[cos (arcsin(x))]/√(1-x²)
Answer: d sin(arcsin(x))/dx=[cos (arcsin(x))]/√(1-x²)
Answer:
The answer is below
Step-by-step explanation:
Calvin school is 2.3 miles directly south of his house. After school, he takes a bus 1.8 miles west of his school to the sport complex.
a) What is the length of a straight line between calvins house and the sports complex? Round to the nearest tenth.
b) Calvin takes piano lessons at a community music school located 3.7 miles directly north of the sports complex. What is the length of a straight line between Calvin's house and the music school? Round to the nearest tenth.
Solution:
a) Calvin school, his house and the sport complex form a right angled triangle. The hypotenuse of the right angled triangle is the length of the line between Calvin's house and the sport complex. Let the length of the line between Calvin's house and the sport complex be x.
Using Pythagoras law for right angled triangle, we get that:
x² = 2.3² + 1.8²
x² = 8.53
x = √8.53
x = 2.9 miles to the nearest tenth
b) This forms a right angled triangle with the hypotenuse = length of a straight line between Calvin's house and the music school. one side of the triangle = 1.8 miles and the other side = 3.7 - 2.3 = 1.4 miles.
Let x = length of a straight line between Calvin's house and the music school. Hence:
x² = 1.8² + 1.4²
x² = 5.2
x = √5.2
x = 2.3 miles to the nearest tenth
