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Levart [38]
2 years ago
12

If triangle HIJ is dilated about the center of the triangle to create triangle H'I'J', dilated line A'B' will

Mathematics
2 answers:
nevsk [136]2 years ago
7 0
Pls. see attachment.

Law Incorporation [45]2 years ago
4 0

If triangle HIJ is dilated about the center of the triangle to create triangle H'I'J', dilated line A'B' will be parallel to AB.Option (D) is correct.

Further explanation:

Given:

The options are as follows,

(A). be perpendicular to AB.

(B). lie on the same line as AB.

(C). shift four units to the left.

(D). be parallel to AB.

Explanation:

If we dilate triangle HIJ then the dilated triangle {\text{H'I'J'}} is bigger than the triangle HIJ.

The triangle HIJ is similar to triangle {\text{H'I'J'}} to each other.

So the line {\text{A'B'}} is parallel to side AB.

If triangle HIJ is dilated about the center of the triangle to create triangle H'I'J', dilated line A'B' will be parallel to AB. Option (D) is correct.

Kindly refer to the image attached below.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Coordinate geometry

Keywords: image vertices, AB, line, passing, point A, point B, triangle HIJ, dilated, perpendicular to AB, lies, same line, shift four units, left, pre-imaged, dilation, center, scale factor, four, coordinates, x-coordinates, y-coordinate, transformation rule.

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3 years ago
The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate
Schach [20]

Answer:

(a)0.16

(b)0.588

(c)[s_1$ s_2]=[0.75,$  0.25]

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix P^k.

(a)

P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)

P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}

If the system is initially running, the probability of the system being down in the next hour of operation is the (a_{12})th$ entry of the P^2$ matrix.

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, S=[s_1$  s_2]

[s_1$  s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$  s_2]

Using a calculator to raise matrix P to large numbers, we find that the value of P^k approaches [0.75 0.25]:

Furthermore,

[0.75$  0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$  0.25]

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

[s_1$ s_2]=[0.75$  0.25]

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