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3 years ago

A survey was conducted at Giant Supermarket where 50 students were randomly chosen and asked

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

Answer:

The answer for both apples and bananas is 21

The answer for only apples or only bananas is 45

Step-by-step explanation:

36 plus 30 minus 45

50-5 is 45

only apples or bananas is 15 + 9

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How do you write the equation of the horizontal line passing through (1,9)?

Leviafan [203]

he equation of any horizontal line is

y = .. a number

The x-value has no effect on the equation or on the line at all, as long as y-value stays the same.

In this case the line passes though the point (−8,9)

which tells us that the y-value we want is 9.

Therefore the equation is y=9

4 0

2 years ago

Find the area. 7 in. 5 in. 12 in.

vitfil [10]

Answer and Step-by-step explanation:

The area formula for a trapezoid is as follows:

A = $\frac{a + b}{2}h$

Where:

A = Area

a = top side length

b = bottom side length

h = height

Plug in the values given to you into the equation and solve.

A = $\frac{7 +12}{2}(5)$

A = $\frac{19}{2}(5)$

A = $\frac{95}{2}$

A = 47.5 $in.^2$ is the answer.

#TeamTrees #PAW (Plant And Water) #ALM (All Lives Matter)

6 0

3 years ago

How are neuroscience and medical science alike?

pishuonlain [190]

Answer:

They're both science

Step-by-step explanation:

5 0

3 years ago

What will be the distance from the center of dilation, Q, to the image of vertex A? 2 units 3 units 4 units 6 units

Kazeer [188]

Answer:

The answer is 4 units

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Using Euler’s Method with a step size of h=0.5, estimate the value for y(3) for the differential equation xy dy/dx= 1+ln(x^2), w

lora16 [44]

Euler's method uses the recurrence relation

$y_{n+1}=y_n+hf(x_n,y_n)$

to approximate the value of the solution $y(x)$ to the ODE $y'=f(x,y)$ .

$xy\dfrac{\mathrm dy}{\mathrm dx}=1+\ln(x^2)\implies y'=\dfrac{1+\ln(x^2)}{xy}=f(x,y)$

With a step size of $h=0.5$ , there will only be two steps necessary to find the approximate value of $y(3)$ based on the initial point $y(2)=5$ . See the attached table below for the computation results.

To demonstrate how the table is generated: Since $y(2)=5$ , you are using $(x_0,y_0)=(2,5)$ .

$y_1=y_0+hf(x_0,y_0)$
$y_1=5+0.5\times\dfrac{1+\ln(2^2)}{2\times5}$
$y_1\approx5.1193$

The next point then uses $x_1=x_0+0.5=2.5$

$y_2=y_1+hf(x_1,y_1)$
$y_1=y_1+0.5\times\dfrac{1+\ln(2.5^2)}{2.5y_1}$
$y_2\approx5.230$

8 0

2 years ago