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podryga [215]
3 years ago
12

You can remember the three numbers to your combination lock, but you can’t remember their order. How many different combinations

of the three numbers will you have to try, at most?
Mathematics
1 answer:
Pie3 years ago
6 0

Answer:

6

Step-by-step explanation:

1-2-3-x-x

1-3-2-x-x

2-1-3-x-x

2-3-1-x-x

3-1-2-x-x

3-2-1-x-x

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Your friend has a fabulous recipe for salsa, and he wants to start packing it up and selling it. He can rent the back room of a
9966 [12]
1000 jars a month..how many jars can he make
6 0
3 years ago
Read 2 more answers
Plz help me solve and show your work.
xz_007 [3.2K]

Hi there!

\large\boxed{h = \frac{15x}{y}}

Recall the volume of a pyramid is:

V = 1/3(bh)

We are given the volume and side length of the base. Find the area of the base:

A = s²

A = (5xy²)² = 25x²y⁴

Plug in the solved for base:

125x³y³ = 1/3(25x²y⁴)h

To isolate for h, begin by multiplying both sides by 3:

375x³y³ = (25x²y⁴)h

Divide both sides by 25x²y⁴. Use the following exponent property:

xᵃ / xᵇ = xᵃ⁻ᵇ

Thus:

375x³y³ / 25x²4⁴ = 15x/y.

The height must be equal to:

h = \frac{15x}{y}

7 0
2 years ago
A jacket is marked down 55% off the original price. If the original price was $160.00, what is the sale price of the jacket befo
Naya [18.7K]

Answer:

72

Step-by-step explanation:

because when you do 55% out of 160 it will give you 88 which you subtract from 160 and then you will end up with 72

3 0
3 years ago
A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the
zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

(c) Average power =  1.06 kW

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

d = \frac{1}{2} ({v-0})t

5.5= \frac{1}{2} (1.6v)

The speed of the sprinter then become:

v = 6.875 m/s

Part (b)

Convert the weight of the sprinter to mass:

m = \frac{w}{g}

m = \frac{706}{9.8}

m = 72 kg

KE (Kinetic Energy) can then be calculated as:

KE = \frac{1}{2} mv^{2}

KE = \frac{1}{2} (72)(6.875)^{2}

KE = 1701.56 J = 1.70 kJ

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

P = \frac{KE}{t} \\\

P = \frac{1701.56}{1.6}

P = 1063.48 W = 1.06 kW

5 0
3 years ago
I am redesigning a rectangular prism in geometry where I have to minimize the surface area while maintaining the same volume. I
Romashka [77]

Strategy:

You will need to make use of the formulas for volume and area of the shapes you have chosen.

... volume of a sphere = (4/3)πr³

... area of a sphere = 4πr²

You will have to use the volume equation to find the radius of the sphere with the desired volume. Then use the area formula to verify the area is smaller than for your rectangular prism. (A sphere has the smallest surface area for a given volume of any figure.)

___

For your pyramid, it's a bit more complicated. You can use the formula for volume to find a relationship between the side length and the height. Then you can solve for height and put that expression into the equation for surface area. Now, you have an equation for surface area as a function of side length, which you can use to choose side lengths that give surface area in the range you want. You may find a graphing utility to be helpful for this.

... volume of a pyramid = (1/3)b^2h . . . . . b is the edge length of the base; h is the verical height.

... area of a pyramid = b^2 + 2bs, where s is the slant height: s=√((b/2)^ +h^2)

___

The cylinder is solved essentially the same way the pyramid is solved, except the formulas are slightly different.

... volume of a cylinder = πr²h

... area of a cylinder = 2πr² + 2πrh

Numbers:

If I did it right, a pyramid with a base edge length of 4 or 5 inches (or somewhere between) should give a smaller surface area for the volume you want.

For the cylinder, the radius may be around 2 or 2.1 inches.

5 0
3 years ago
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