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krek1111 [17]
3 years ago
13

sports warehouse had a sale on two models of baseball gloves. Model A sold for $30.00, and model B sold for $45.25. A total of 5

2 gloves were sold. The total amount of sales earned on the gloves, excluding tax, was $2,078.50. How many model B baseball gloves were sold​
Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

18 model A gloves and 34 model B gloves

Step-by-step explanation:

Set up 2 equations based on the given information

Let 'x' represent the number of Model A gloves sold

Let 'y' represent the number of Model B gloves sold

Then..

$30x + $45.25y = $2,078.50  represents the total sold in dollars

    x    +     y       =    52  represents the total number of gloves sold

Solve the second equation for either variable...

   x = 52 - y            

Now plug this into the first equation...

$30(52 - y) + $45.25y = $2,078.50            {x became 52 - y}

Now solve for y...

$1,560 - $30y + $45.25y = $2,078.50

     $15.25y = $518.50   (combine y terms, subtract $1,560 from both sides)

            y =  34             (divide both sided by $15.25, dollar signs cancel out)

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Factor each expression 36abc +54ad
olya-2409 [2.1K]

Answer:

18a(2bc + 3d)

Step-by-step explanation:

36abc + 54ad

Step 1: Find the Highest Common Factor of each

36abc = 2×2×3×3×a×b×c = 18a × 2bc

54ad = 2×3×3×3×a×d = 18a × 3d

HCF = 2×3×3×a = 18a

Step 2: Factor out with HCF

18a(2bc + 3d)

7 0
3 years ago
PLS HELP IT’S DUE TMR!!
ValentinkaMS [17]

Answer:

Use ≈ (approximately equal) sign as the scientific notation.

Step-by-step explanation:

(a) 0.001872 ≈ 0.0019

(b) 0.3411 ≈ 0.34

(c) 0.000845 ≈ 0.00085

*Zeros before non-zero numbers are not significant.

*Zeros appearing between two non-zero digits are significant.

Hope this helps!!

6 0
2 years ago
Marni has 11 ounces of walnuts. She needs 6 ounces for one recipe and pound for another. There are 16 ounces in 1 pound.
Ahat [919]
11-6=5 ounces. She doesn’t have enough for both of the recipes. She will need 11 more ounces to be able to make the recipes. 5+11=16 and 16 ounces are in a pound.
4 0
2 years ago
Read 2 more answers
Formulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x- an
slega [8]

Answer:

1) There were 33 $4,000 investors and 27 $8,000 investors.

2) The solution in x = 4, y = 9.

3) There were 24 nickels and 56 dimes.

Step-by-step explanation:

1) A lawyer has found 60 investors for a limited partnership to purchase an inner-city apartment building, with each contributing either $4,000 or $8,000. If the partnership raised $348,000, then how many investors contributed $4,000 and how many contributed $8,000?

I am going to say that:

x is the number of investors that contributed 4,000.

y is the number of investors that contributed 8,000.

Building the system:

There are 60 investors. So:

x + y = 60

In all, the partnership raised $348,000. So:

4000x + 8000y = 348000

I am going to simplify by 4000. So:

x + 2y = 87

Solving the system:

The elimination method is a method in which we can transform the system such that one variable can be canceled by addition. So:

1)x + y = 60

2)x + 2y = 87

I am going to multiply 1) by -1. So we have

1)-x - y = -60

2)x + 2y = 87

By addition, the x are going to cancel each other

-x + x - y + 2y = -60 + 87

y = 27

For x:

x + y = 60

x = 60-y = 60-27 = 33

There were 33 $4,000 investors and 27 $8,000 investors.

2) Solve the system by row-reducing the corresponding augmented matrix.

2x + y = 17

x + y = 13

This system has the following augmented matrix:

\left[\begin{array}{ccc}2&1&17\\1&1&13\end{array}\right]

To help the row reducing, i am going to swap the first with the second line:

L1  L2

So we have:

\left[\begin{array}{ccc}1&1&13\\2&1&17\end{array}\right]

Now, reducing the first column.

L2 = L2 - 2L1

So we have:

\left[\begin{array}{ccc}1&1&13\\0&-1&-9\end{array}\right]

Now we do:

L2 = -L2

And the matrix is:

\left[\begin{array}{ccc}1&1&13\\0&1&9\end{array}\right]

Now to reduce the second column, we do:

L1 = L1 - L2

\left[\begin{array}{ccc}1&0&4\\0&1&9\end{array}\right].

So the solution is:

x = 4, y = 9.

3) A jar contains 80 nickels and dimes worth $6.80. How many of each kind of coin are in the jar?

I am going to say that x is the number of nickels and y is the number of dimes.

Each nickel is worth 5 cents and each dime is worth 10 cents.

Building the system:

There are 80 coins in all:

x + y = 80

They are worth $6.80. So:

0.05x + 0.10y = 6.80

Solving the system:

1)x + y = 80

2)0.05x + 0.10y = 6.80

I am going to divide 1) by -10, so we can cancel y. So:

1)-0.10x - 0.10y = -8

2)0.05x + 0.10y = 6.80

Adding:

-0.10x + 0.05x - 0.10y + 0.10y = -8 + 6.80

-0.05x = -1.2 *(-100)

5x = 120

x = \frac{120}{5}

x = 24

Also

x + y = 80

y = 80-x = 80-24 = 56

There were 24 nickels and 56 dimes.

8 0
3 years ago
Answer this question, and I will give brainleast.
Sunny_sXe [5.5K]

Answer:

24/25

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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