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Goryan [66]
3 years ago
6

A rectangular prism has dimension of 8 cm by 9 cm. what is the volume?

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

34

Step-by-step explanation:

8+8=16

9+9=18

16+18=34

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Can someone please help me answer this question, i know it seems a little bit basic but I still need some help
maria [59]
Hi,

Rectangular prism or Cuboid has a volume that can be calculated by multiplying it's dimensions.

v = l \times w \times h
In your case...

v = 5 \times 3 \times 4  =  {60}^{3}
Answer = 60m3

Hope this helps.
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2 years ago
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Lilit [14]

Answer:

Graph A passes THrough the Center making it proportional when graph B is not passing

Step-by-step explanation:

6 0
2 years ago
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Plz help ASAP thxs."..
Sliva [168]

Answer:

A

Step-by-step explanation:

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2 years ago
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One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides
Elina [12.6K]
<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

  • The side of the square is 10 ft.
  • One of the vertices of an equilateral triangle is on the vertex of a square.
  • Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

\mathbf{(1)} \ x^2=100+y^2

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

y+(10-y)=10

Therefore, for Triangle 3, we have that by Pythagorean theorem:

(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2

Matching equations (1) and (2):

2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0

Using quadratic formula:

y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68

Finding x from (1):

x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0
3 years ago
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-37=5w-7 <br><br> w=<br><br><br> Please I need an answer ASP
grin007 [14]

Answer:

-6

Step-by-step explanation:

-37+7=5w

-30=5w

w=-30÷5

w=-6

5 0
2 years ago
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