If width is w the length can be represented as 5/2+2w.
Formula for perimeter is 2l + 2w
So it would be 2w + 2(5/2 + 2w)
OR 2w + 5 + 4w
OR 6w + 5
See if this helps ;)
Answer:
Apologiabiology Ambitious
v=vanilla
c=chocolate
A.
4v+c=45
v+c=27
b.
multiply 2nd equation by -1 and add to first
4v+c=45
-v-c=-27 +
3v+0c=18
3v=18
divide both sides by 3
v=6
sub bac
v+c=27
6+c=27
minus 6
c=21
21chocolate
6 vanila
Step-by-step explanation:
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)
your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°
-> insert those values, with c substituted with b+3 to remove c
c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE
DE=CE+3=36+3=39
Answer:
sucky my ducky ;))))
Step-by-step explanation:
