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creativ13 [48]
3 years ago
11

Pensils are sold in packages of 10 and erasers are sold in packages of 6. What is the least number of pensils and erasers you ca

n buy so that there is one pencil for each eraser with none left over.
Mathematics
1 answer:
asambeis [7]3 years ago
8 0
To understand the problem consider the following cases.

i)

If we buy 1 packet of pencils, and 2 packet of erasers, 

we have 1*10=10 pencils and 2*6=12 erasers.

ii)

If we buy 3 packet of pencils, and 4 packet of erasers, 

we have 3*10=30 pencils and 4*6=24 erasers.


So let a and b be the correct number of packets of pencils and erasers respectively.

That is the least numbers a and b, such that 10a=6b.

10a=6b

divide both sides by 10:

a= \frac{6b}{10}= \frac{3b}{5}

divide both sides by b:

\frac{a}{b} =  \frac{3}{5}

the ratio a:b cannot be simplified any further. This means that the smallest (natural) numbers a and b such that \frac{a}{b} = \frac{3}{5} are a=3 and b=5


Answer:


3 packages of pencils, 5 packages of erasers.

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Answer:

0.761

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Question<br> Find the sum horizontally.<br> (3x – x°- 2x?)+(-x° - 3x) =
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3 years ago
HELlPpPp BRAINLIEST thank you &lt;3<br><br> m – 9 = 11
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m=20

Step-by-step explanation:

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The sides of the parallelogram are 63cm and 76cm. if they intersect at an angle of 63 degrees, find the area of the parallelogra
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Area =  ab Sin O
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3 0
3 years ago
Helpppp meeeee outttttt pleaseeeee ASAPPPP!!!!
Ilya [14]

Answer:

\boxed{\sf sin\ C =\frac{40}{41}}

Step-by-step explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .

\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,

\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}

Substitute the respective values ,

\sf\longrightarrow \boxed{\blue{\sf sin\ C =\dfrac{40}{41}}}

<u>Hence the required answer is 40/41.</u>

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