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hoa [83]
3 years ago
13

Which points are a distance of 5 units from (2, 3) if d = square root (x2 - x1)2 + (y2 - y1)?

Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

Step-by-step explanation:

hello :

note :

note : distance between A(X1,Y1) an B (X2,Y2) is :  

AB= √((X2 - X1)² + (Y2 - Y1)²)    (given point  B(2 , 3)

in this exercice : X1 = 2     X2 = ?      Y1 = 3      Y2 = ?   d=AB=5

d² = (X2 - 2)² + (Y2 - 3)² =25

the points are a distance of 5 units from B (2, 3) if d = 5 :

the points are located on a circle with center B and radius 5

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lana66690 [7]

Answer:

y=\frac{13}{6}x             y= \frac{11}{5}x          y = \frac{21}{9}x          y = \frac{19}{8}x

Step-by-step explanation:

Given

The attached graph

Required

Equations with higher unit rate

First, calculate the unit rate of the graph

m = \frac{y_2 - y_1}{x_2 - x_1}

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(x_1.y_1) = (0,0)

(x_2.y_2) = (7,15)

So:

m = \frac{15 - 0}{7 - 0}

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For the given options.

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The unit rates grater than the graph's from small to large are:

y=\frac{13}{6}x             y= \frac{11}{5}x          y = \frac{21}{9}x          y = \frac{19}{8}x

m=\frac{13}{6}              m= \frac{11}{5}           m = \frac{21}{9}            m = \frac{19}{8}

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