The point lies in the second quadrant
We are given the description of a diagram where the base of a parallelogram lies on the x-axis with the left vertex on the origin. We are also given the three consecutive coordinates of the vertices which are
(h, j ), (0, 0), and (k, 0)
Based on the coordinates, the point (h, j) is j units from the y-axis
Answer:
Given a line and a point not on it, no lines parallel to the given line can be drawn through the point. you get an elliptic geometry.
Step-by-step explanation:
In slope-intercept form, we have these values (y = mx + b):
m = slope
b = y-intercept
Change the equation from standard form to slope-intercept form.
-9x + 7y = 28
-9x + 9x + 7y = 28 + 9x
7y = 28 + 9x
7y/7 = 28/7 + 9x/7
y = 4 + 9/7x
y = 9/7x + 4
Therefore, the y-intercept is 4.
Best of Luck!
