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➷ Just multiply the price by 3:
1.35 x 3 = 4.05
It would cost $4.05
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➶ Hope This Helps You!
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Answer:
x-intercepts = 1,2, and 4, y-intercept = -8
Step-by-step explanation:
x^3 - 7x^2 - 14x - 8 in factored form is equal to (x-1)(x-2)(x-4).
Solving for x-intercepts:
- We are actually able to solve for all x-intercepts without the given factor. But since we are given one of the factors, our job becomes much easier.
- Using synthetic division, or long division, we factor out the x-intercept 4. Which leaves us with the polynomial x^2 - 3x + 2.
- From here we can separate the polynomial into two binomials.
- x^2 - 3x + 2 = (x-1)(x-2). Giving us all 3 x-intercepts.
- Using Descartes' rules we can identify before even starting the problem how many real x-intercepts there are (Not needed for this problem).
Solving for y-intercept:
- The y-intercept is always the coefficient that does not have any assigned x-variables.
- The coefficient is -8, thus the y-intercept.
- If unsure of the y-intercept, you can always plug in x = 0. Solving for the y-intercept will give you the value of f(0).
- If there is no coefficient, the y-intercept is equal to zero.
ANSWER:
6_34/99
STEP:
So yes. When a decimal is repeating, you can take the repeating number (most likely a decimal) and put 99 under it. Since 99 cannot be solved, you put 99. So, 34/99. Though we are not finished. There is still the whole 6 number left. So, you do 6_34/99.
Proof:
10x=6.6...
-x=-0.6...
9x=6
x=6/9=1/3.
The average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.
<h3>What is the average rate of change?</h3>
The average Rate of Change of the function f(x) can be calculated as;
Interval -3 ≤ x ≤-1
a = -3, b = -1
f(a) = f(-3) = -20
f(b) = f(-1) = 0
Step 2: Find Average
Therefore, the average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.
Learn more about average rate;
brainly.com/question/20784578
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In mathematics: Arithmetic progression, sequence of numbers such that the difference of any two successive members of the sequence is a constant. Geometric progression, sequence of numbers such that the quotient of any two successive members of the sequence is a constant. so i chose b)Sequences
