h(x) = 3 * (2)^x
Section A is from x = 1 to x = 2
h(1) = 3 * (2)^1 = 3 * 2 = 6
h(2) = 3 * (2)^2 = 3 * 4 = 12
so
the average rate of change = (12 - 6)/(2 - 1) = 6
Section B is from x = 3 to x = 4
h(3) = 3 * (2)^3 = 3 * 8 = 24
h(4) = 3 * (2)^4 = 3 * 16 = 48
so
the average rate of change = (48 - 24)/(4 - 3) = 24
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)
the average rate of change of section B is 24 and the average rate of change of section A is 6
So 24/6 = 4
The average rate of change of Section B is 4 times greater than the average rate of change of Section A
It's exponential function, not a linear function; so the rate of change is increasing.
That is the combination of 10 over 3, which is calculated as the quotient of factorials:
n!/k!(n-k)!
where n = 10 and k = 3:
= 10!/3!(10 - 3)!
= 10!/3!*7!
= (10*9*8)/(3*2*1)
= 720/6
= 120
therefore there a re 120 possible different groups
Answer: x=8
Step-by-step explanation:
Distribute 5(x) and 5(-2)
-12 + 6x = 6 + 5x + (-10) OR 5x - 10
Flip if you'd like
6x - 12 = 6 + 5x - 10
Combine like terms
6x−12=(5x)+(6+−10)
6x - 12 = 5x - 4
Subtract 5x from both 6 and 5
6x - 5x = 5x - 5x
5x cancels out, so you're left with x, 12, and -4
x - 12 = -4
Add 12 to 12 and -4
12 + 12 = -4 + 12
12 cancels out
-4 + 12 = 8
x = 8
<span>3y-6x=9
</span><span>3y = 6x + 9
y = 2x + 3
answer
</span> y = 2x + 3
Answer:
6 + 3 (-8 x -2)
Step-by-step explanation:
6 + 3 (-8 x -2)
= 6+3 ( 16 )
= 9 ( 16 )
= 144
