2(5x+4) =10x+6 is this equation always, sometimes or never true? Asap please

2 answers:

6 0

The equation is never true because you have to multiply 2 with all numbers in the parentheses. Therefore

2(5x +4) = 10x + 8.

Because 2 x 4 is not 6 but 8

BartSMP [9]4 years ago

5 0

Never true because it does not equal to it.

You might be interested in

Hey can someone please help, i dont know how to do this

yKpoI14uk [10]

Use the tenth’s theory and herons theory u will get it

6 0

3 years ago

Helppp please I have limited time

Sophie [7]

Answer:

p = T - a - b

Step-by-step explanation:

Hope that helps, not sure if it is correct though.

7 0

4 years ago

Read 2 more answers

Part A: A circle is the set of all points that are the same distance from one given point. Find an example that contradicts this

IRINA_888 [86]

Answer:

a sphere

the definition needs to restrict all of the points to a plane

Step-by-step explanation:

In 3-dimensional Euclidean space, a sphere is the set of all points the same distance from a given point. The given definition of a circle only applies when the given point and the solution set are in the same plane, and the geometry is Euclidean.

8 0

3 years ago

Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel

Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e ( $x_o, y_o, z_o$ ) and are parallel to $\dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}$

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

$x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct$

x = 4 + t

y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

$\begin {vmatrix} x = 4+ t \\ \\ \dfrac{x-4}{1} = t \begin {vmatirx} \end {vmatrix}$ $\begin {vmatrix} y = - 5+2t \\ \\ \dfrac{y+5}{2} =t \end {vmatrix}$ $\begin {vmatrix} z =2+t \\ \\ \dfrac{z-2}{1} =t \end {vmatrix}$