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Aloiza [94]
4 years ago
6

a jug contains 2.45 liters of cranberry juice. A bottle contains 2 wholes 13/25 liters of grape juice. which container holds les

s fruit juice? How much less?
Mathematics
1 answer:
IgorLugansk [536]4 years ago
5 0
The cranberry juice contains less fruit juice

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Find two consecutive even integers such that their Sum is equal to the difference of three times larger and two times the smalle
aniked [119]

Answer:

4 and 6

Step-by-step explanation:

a and (a+2) are consec. even integ.

a+a+2=3(a+2)-2a

2a+2=3a+6-2a

2a+2=a+6

a=4

a+2= 6

5 0
3 years ago
HELP ASAPP !! Select the correct answer.
Vika [28.1K]

Answer:

A) I=\frac{P}{4\pi r^2}

Step-by-step explanation:

To isolate I, we need to divide both sides by 4\pi r^2. Therefore, the answer is I=\frac{P}{4\pi r^2}.

4 0
3 years ago
What is the best estimate for the value of r in the scatter plot?
Wittaler [7]

From the observation of the dispersion graph it is concluded that the answer to this question is option D. r = -0.5.

The correlation coefficient "r" is a measure of the linear relationship between two random variables.

When the correlation is positive, the value of "r" is between 0 and 1. This means that when one variable increases the other too.

When the correlation is negative, the value of "r" is between -1 and 0. This means that one variable decreases as the other increases.

When there is no correlation the value of "r" is 0


In this case, the dispersion chart shows that the variable "y" decreases as the variable "x" increases. Therefore the value of "r" must be negative. Of all the options, the only one that presents a value of negative r is option D:

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5 0
4 years ago
Horario is solving the equation -3/4 + 2/5 = 7/20x -1/2
sergeinik [125]

Answer:

x = 3/7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A population of deer inside a park has a carrying capacity of 200 and a growth rate of 3%. If the initial population is 80 deer,
otez555 [7]

Answer:

The population of deer at any given time = 200(e^0.03t)  ÷ (1.5 + (e^0.03t))

Step-by-step explanation:

This is an example of logistic equation on population growth

carrying capacity, k = 200

Rate, r = 3% = 0.03

Initial Population, P1 =  80

P(t) =?

P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))

P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))

     = (16000(e^0.03t))  ÷ (120 + 80(e^0.03t))

      = 200(e^0.03t)  ÷ (1.5 + (e^0.03t))

8 0
3 years ago
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