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2 years ago

What is 15 x minus 3 y = 0 written in slope-intercept form? y = 5x y = negative 5 x x = one-fifth y x = 5 y

Mathematics

1 answer:

DanielleElmas [232]2 years ago

8 0

Answer:

y=5(x)

Step-by-step explanation:

on edge :]

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Michael is 4 times as old as brandon and is also 27 years older than brandon<br> how old is brandon?

Komok [63]

Let the age of Brandon be x.

Therefore the age of Michael is 4x

Also the age of Michael is 27+x

4x=27+x

3x=27

X=9

Brandon age is 9years while Michael's age is 36

6 0

2 years ago

Please help me I would really appreciate it this really affects my grade need the answer the ASAP

Drupady [299]

Answer:

27/6, 4 3/6, or simplified version 4 1/2

Step-by-step explanation:

Always convert the mixed numbers into an improper fraction before you solve, this makes it easier to solve.

2 4/6 = 16/6

1 5/6 = 11/6

3 4/6 = 22/6

Now we solve. Remember, you do NOT add the denominator, leave it as 6 not 12. You only add the numerator.

16/6 + 11/6 = 27/6, 4 3/6 or simplified as 4 1/2

22/6 + 5/6 = The same as above.

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3 years ago

Square inch for 30 stones

Anna71 [15]

1 stone = 20 square inches

1 stone * 30 = 20 square inches * 30

30 stones = 600 square inches

8 0

2 years ago

Use the power-reducing formulas to rewrite each of the expressions in terms of the first power of the cosine. Sin^4cos^4

Katen [24]

Answer:

1/128 * (3 - 4cos2x + cos4x)

Step-by-step explanation:

See attachment for steps

6 0

2 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

2 years ago