What is the likelihood that the children in square 2 will have earlobes that are not attached?
1 answer:
You might be interested in
Answer:
4.27%
Step-by-step explanation:
We have been given that college students average 8.6 hours of sleep per night with a standard deviation of 35 minutes. We are asked to find the probability of college students that sleep for more than 9.6 hours.
We will use z-score formula to solve our given problem.
z = z-score,
x = Random sample score,
= Mean,
= Standard deviation.
Before substituting our given values in z-score formula, we need to convert 35 minutes to hours.
Now, we need to find .
Using formula , we will get:
Using normal distribution table, we will get:
Therefore, 4.27% of college students sleep for more than 9.6 hours.