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Hoochie [10]
3 years ago
13

What is the likelihood that the children in square 2 will have earlobes that are not attached?

Mathematics
1 answer:
notka56 [123]3 years ago
4 0
Answer : 2/4 children will have earlobes that are not attached
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Equation Given: <img src="https://tex.z-dn.net/?f=h%28t%29%3D-4.9t%5E%7B2%7D%2B358" id="TexFormula1" title="h(t)=-4.9t^{2}+358"
Vilka [71]

Answer:

At 3.44 seconds, the penny is at a height of 300 meters above the ground.

Step-by-step explanation:

Basically, we have to solve an equation here:

-4.9t^{2} + 358 = 300

Hence,

-4.9t^{2} = 300 - 358

t^{2} = \frac{-58}{-4.9}

t = 3.44

Hence, at 3.44 seconds, the penny is at a height of 300 meters above the ground.

Hope this helped!

4 0
2 years ago
The school that Joe goes to is selling tickets to a choral performance. On血e first day of ticket
ArbitrLikvidat [17]

Answer:

The price of one senior citizen ticket is $8, and the price of one child ticket is $11.

Step-by-step explanation:

You are looking for two things: the price of a senior citizen ticket and the price of a child ticket.

We need to write two equations using two variables.

Let s = price of 1 senior citizen ticket.

Let c = price of 1 child ticket.

First day of ticket sales:

6 senior citizen tickets, 8 child tickets, total sales of $136

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 8 tickets cost 8c.

The total sales is 6s + 8c.

The total sales is $136, so our first equation is

6s + 8c = 136

Now we do the same for the second day of ticket sales.

6 senior citizen tickets, 9 child tickets, total sales of $147.

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 9 tickets cost 9c.

The total sales is 6s + 9c.

The total sales is $147, so our second equation is

6s + 9c = 147

The system of equations is

6s + 8c = 136

6s + 9c = 147

Multiply both sides of the first equation by -1. Write the second equation below it. Then add the equations.

       -6s - 8c = -136

(+)     6s + 9c = 147

----------------------------

                  c =   11

c = 11, so the cost of a child ticket is $11.

Now substitute 11 for c in the first equation, and solve for s.

6s + 8c = 136

6s + 8(11) = 136

6s + 88 = 136

6s = 48

s = 8

The price of a senior citizen ticket is $8.

The price of a senior citizen ticket is $8, and the price of a child ticket is $11.

6 0
3 years ago
If you are adding two fractions that are both greater than one half what must be true about the sum?
Ann [662]
It will automatically be over 1
4 0
3 years ago
The sum of the reciprocals of two consecutive integers is 9/20. Determine the consecutive integers algebraically.
DochEvi [55]
The answer is 2 1/5.
3 0
3 years ago
Read 2 more answers
Given the Arithmetic series A 1 + A 2 + A 3 + A 4 A1+A2+A3+A4 14 + 18 + 22 + 26 + . . . + 86 What is the value of sum?
postnew [5]

Answer:

950

Step-by-step explanation:

The common difference is 4, so the general term can be written:

... an = 14 + 4(n -1)

The value of n for the last term is ...

... 86 = 14 + 4(n -1) . . . . . the computation for the last term, 86

... 72 = 4(n -1) . . . . . . . . . subtract 14

... 18 = n -1 . . . . . . . . . . . divide by 4

... 19 = n . . . . . . . . . . . . . add 1

Your series has 19 terms. The first term is 14 and the last is 86, so the average term is (14+86)/2 = 50. Since there are 19 terms, the sum of them is ...

... 19×50 = 950

7 0
3 years ago
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