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4 years ago

Explain why the mass and weight should not be used interchangeably?

1 answer:

4 0

Mass is a property of an object, a cloud of gas, a puddle of liquid, or a lump of goo, and doesn't necessarily change when the object moves to a different location or environment. It depends only on the object itself.

Weight is completely a product of what else is in the nearby location,so it can easily change. It's the result of the gravitational forces between two objects . . . the first one with the constant mass, and another one that also has mass. The forces between them, and therefore the weight, depend on both masses, AND on the distance between them.

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A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p

kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

$y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2$

$V(t) = V_0 + a * t$ ,

Where $y_0$ its our initial height, $V_0$ our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

$y(t) = 38 \frac{m}{s} * t - \frac{1}{2} g t^2$

$V(t) = 38 \frac{m}{s} - g * t$

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

$0 m = 38 \frac{m}{s} - g * t$

and obtain:

$t = 38 \frac{m}{s} / g$

$t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}$

$t = 3.9 s$

Plugin this time on our first equation we find:

$y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2$

$y=73.67 m$

6 0

3 years ago

The weight of an object four earth radii from the center of the earth is:

Komok [63]

Answer:

D. 1/16 It's weight on the surface.

Explanation:

As we know that the gravity due to earth at its surface is given as

$g = \frac{GM}{R^2}$

now at the distance of 4 radius of earth the gravity is given as

$g' = \frac{GM}{(4R)^2}$

so we can say that

$g' = \frac{g}{16}$

so here gravity becomes 1/16 times of the gravity due to earth on its surface

now we know that weight on the surface of earth is given as

$W = mg$

also the weight now at the given height is given by

$W' = mg/16$

so here correct answer will be

D. 1/16 It's weight on the surface.

8 0

4 years ago

The frequency of violet light is 7.5 x 1014 hertz. What is its wavelength in a vacuum?

Alchen [17]

Answer:So, the wavelength is 400 nm and 4000 A°

Explanation:

3 0

3 years ago

A person walks first at a constant speed of 5.00 m.s-1

Soloha48 [4]

The average speed of the person over the entire trip is 3.75 m/s.

<h3>Average speed of the person</h3>

Average speed = total distance/total time

Average speed = (d + d)/(d/Va + d/Vb)

where;

d is the distance in a single trip
Va is speed from point A
Vb is the speed from point B

Average speed = (2Vavb)/(Va + Vb)

Average speed = (2 x 5 x 3)/(5 + 3)

Average speed = 3.75 m/s

Thus, the average speed of the person over the entire trip is 3.75 m/s.

Learn more about average speed here: brainly.com/question/6504879

#SPJ1

4 0

2 years ago

HELP MEE

lbvjy [14]

The interior structure of the Earth is layered in spherical shells. These layers can bedefined by their chemical and their rheological properties. Earth has an outer silicate solid crust, a highly viscous mantle, a liquid outer core that is much less viscous than the mantle, and a solid inner core.

5 0

3 years ago