<h2>
The magnitude 24 (
) of the acceleration of the particle when the particle is not moving.</h2>
Explanation:
Given,
A particle moving along the x-axis has a position given by
m ........ (1)
To find, the magnitude (
) of the acceleration of the particle when the particle is not moving = ?
Differentiating equation (1) w.r.t, 't', we get

⇒
....... (2)
⇒ 
⇒ 
⇒ t = 2 s
Again, differentiating equation (2) w.r.t, 't', we get

Put t = 2, we get

Thus, the magnitude 24 (
) of the acceleration of the particle when the particle is not moving.
Answer:
The velocity of the boy and the bicycle is 2.2 m/s.
Explanation:
We have,
Mass of child is 30 kg and the mass of bicycle is 20 kg. The combined momentum of the child and the bicycle is 110 kg-m/s.
It is required to find the velocity of the boy and the bicycle. The momentum of an object is given in terms of mass and its velocity. So,

M is combined mass of child and bicycle

So, the velocity of the boy and the bicycle is 2.2 m/s.
Answer:
Since the area of the perfect square is 11650, and all of a squares sides ar equal, we just need to find the square root.
The square root of 11650 is 107.935166.
One side of the square is 107.935166
107.935166 x 107.935166 = 11650
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<h2><em>C. translational motion</em></h2><h2><em>HOPE IT HELPS !!!!!</em></h2>