The sun provides a handy benchmark for describing other stars. The mass of this solar system's sun gives us a unit for measuring other stars' masses.
Answer:
The reading in the scale is going to be the same, or if it experiences some change it would be minimum. The reason is because the truck will act as a big closed cage, therefore, when the pigeons fly, the air they move with their wings in order to keep flying, exerts the same force on the closed cage, that if they were standing on the ground.
If the truck however, allows the air flow, the weight might change, because under this scenario, the air flowing could represent less force exerted on the balance.
Explanation:
Answer:
2.01
Explanation:
First, we need to find the centripetal acceleration.
We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute
Now this speed gotten in rpm will be converted to m/s, to ease the calculation
30 rpm = πdN/60 m/s
30 rpm = (3.142 * 4 * 30)/60
30 rpm = 377.04/60
30 rpm = 6.284 m/s
a(c) = v²/r
a(c) = 6.284²/2
a(c) = 39.49 / 2
a(c) = 19.74 m/s²
F = ma
F = 50 * 19.74
F = 987 N
Also, Normal Force, F(n) =
F(n) = mg
F(n) = 50 * 9.81
F(n) = 490.5
We then use this to find the coefficient of static friction, μ
μ = F/F(n)
μ = 987 / 490.5
μ = 2.01
Answer:
average speed = 1.73m/s
average velocity = 3.33m/s
Explanation:
<em>we'll</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>average</em><em> </em><em>speed</em><em> </em><em>first</em>
<em>average</em><em> </em><em>speed</em><em> </em><em>=</em><em> </em><em>total</em><em> </em><em>distance</em><em> </em><em>/</em><em> </em><em>total</em><em> </em><em>time</em><em> </em>
<em>his</em><em> </em><em>total</em><em> </em><em>distance</em><em> </em><em>is</em><em> </em>300m + 100m
= 400m
and total time should be taken in seconds as you know
((2×60)+50) + 60s
= 230s
so let's divide,
400m/230s
1.73 m/s
next, mean velocity
that is,
mean velocity = final- initial displacement/time
we have to note <em>displacement</em><em> </em>( this is the distance between the initial point to final point) here
the displacement is 300-100
so, 200m
we already calculated total time
but that cant be taken here
230 - 170
is the original time to travel 200m
that is, 60s
so we divide
200/60
3.33m/s
Answer:
They both require displacement with respect to time
